console.log(1)asyncfunctionfun1(){co...
发布于 2022-03-03 16:06:15
console.log(1) async function fun1(){ console.log(6) await fun2() console.log(7) } setTimeout(()=>{ console.log(9) },0) async function fun2(){ new Promise((resolve)=>{ console.log(2) resolve(3) setTimeout(()=>{ console.log(4) },0) }).then((data)=>{ console.log(data) }).then(()=>{ console.log(5) }) } fun1() console.log(8)
如上js代码会输出什么?
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