描述如下:intia[]={0,2,4,6,8,10}int*ip1=&...
发布于 2022-03-03 15:18:00
描述如下:
int ia[] = {0,2,4,6,8,10}
int* ip1 = &ia[3]
int* ip2 = &ia[1]
int diff = ip1-ip2
那么在32位平台下diff的值是:
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