程序的输出为( )
发布于 2022-03-03 14:10:08
#include<iostream> using namespace std int n = 300 int solve(int x) { return x * (n - x) } int main() { int l = 1, r = n int mid1, mid2 int t = 50 while (t--) { mid1 = l + r >> 1 mid2 = mid1 + r >> 1 if (solve(mid1) > solve(mid2)) { r = mid2 } else { l = mid1 } } cout << l << endl return 0 }程序的输出为()
登录后免费查看答案
关注者
0
被浏览
6