Zend框架SQL选择查询构造（WHERE子句）

Question

我正在尝试生成一个查询，该查询从用户名中全选，其中姓氏的姓氏的任何组合都与特定搜索词匹配

$select = $select->where('last_name LIKE ?', '%'.$term.'%')->orWhere('first_name LIKE ?', '%'.$term.'%')
                        ->orWhere("CONCAT(first_name,' ', last_name) LIKE ?", '%'.$term.'%')
                        ->orWhere("CONCAT(last_name,' ', first_name) LIKE ?", '%'.$term.'%');

还必须满足另一个条件，该条件在另一个where子句中指定

$select = $select->where("deleted = 0 AND scholar = 0");

生成以下SQL语句

SELECT `user`.* FROM `user` WHERE (last_name LIKE '%frank%') OR (first_name LIKE '%frank%') OR (CONCAT(first_name,' ', last_name) LIKE '%frank%') OR (CONCAT(last_name,' ', first_name) LIKE '%frank%') AND (deleted = 0 AND scholar = 0) ORDER BY `date_created` desc LIMIT 25

这并没有返回期望的结果，因为我得到了Scholar = 1的行；

我认为查询应该是

SELECT `user`.* FROM `user` WHERE ((last_name LIKE '%frank%') OR (first_name LIKE '%frank%') OR (CONCAT(first_name,' ', last_name) LIKE '%frank%') OR (CONCAT(last_name,' ', first_name) LIKE '%frank%')) AND  (deleted = 0 AND scholar = 0) ORDER BY `date_created` DESC LIMIT 25

使用$ select对象实现此目的的正确语法是什么。

Answer 1

您可以使用quoteIn来准备您的条件，然后像这样使用它们：

    $first_name_cond = $db->quoteInto('first_name LIKE ?', '%'.$term.'%');
    $last_name_cond = $db->quoteInto('last_name LIKE ?', '%'.$term.'%');

    $concat_cond1 = $db->quoteInto("CONCAT(first_name,' ', last_name) LIKE ?", '%'.$term.'%');

    $concat_cond2 = $db->quoteInto("CONCAT(last_name,' ', first_name) LIKE ?", '%'.$term.'%');


    $select = $select->where($first_name_cond.' OR '.$last_name_cond.' OR '.

             $concat_cond1.' OR '.$concat_cond2)->where("deleted = 0 AND scholar = 0");