Python Pandas:如何删除nan和-inf值

发布于 2021-01-29 18:30:34

我有以下数据框

           time       X    Y  X_t0     X_tp0  X_t1     X_tp1  X_t2     X_tp2
0         0.002876    0   10     0       NaN   NaN       NaN   NaN       NaN
1         0.002986    0   10     0       NaN     0       NaN   NaN       NaN
2         0.037367    1   10     1  1.000000     0       NaN     0       NaN
3         0.037374    2   10     2  0.500000     1  1.000000     0       NaN
4         0.037389    3   10     3  0.333333     2  0.500000     1  1.000000
5         0.037393    4   10     4  0.250000     3  0.333333     2  0.500000

....
1030308   9.962213  256  268   256  0.000000   256  0.003906   255  0.003922
1030309  10.041799    0  268     0      -inf   256  0.000000   256  0.003906
1030310  10.118960    0  268     0       NaN     0      -inf   256  0.000000

我尝试了以下

df.dropna(inplace=True)
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.40)

X_train = X_train.drop('time', axis=1)
X_train = X_train.drop('X_t1', axis=1)
X_train = X_train.drop('X_t2', axis=1)
X_test = X_test.drop('time', axis=1)
X_test = X_test.drop('X_t1', axis=1)
X_test = X_test.drop('X_t2', axis=1)
X_test.fillna(X_test.mean(), inplace=True)
X_train.fillna(X_train.mean(), inplace=True)
y_train.fillna(y_train.mean(), inplace=True)

但是,ValueError: Input contains NaN, infinity or a value too large for dtype('float32').每当我尝试拟合回归模型时 ,我仍然会收到此错误fit(X_train, y_train)

我们如何同时删除NaN-inf值?

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1 个回答
  • 面试哥
    面试哥 2021-01-29
    为面试而生,有面试问题,就找面试哥。

    使用pd.DataFrame.isin并检查带有的行pd.DataFrame.any。最后,使用布尔数组对数据帧进行切片。

    df[~df.isin([np.nan, np.inf, -np.inf]).any(1)]
    
                 time    X    Y  X_t0     X_tp0   X_t1     X_tp1   X_t2     X_tp2
    4        0.037389    3   10     3  0.333333    2.0  0.500000    1.0  1.000000
    5        0.037393    4   10     4  0.250000    3.0  0.333333    2.0  0.500000
    1030308  9.962213  256  268   256  0.000000  256.0  0.003906  255.0  0.003922
    


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