快速返回没有Python中特定元素的列表的方法

Question

如果我有任意顺序的卡片套装列表，如下所示：

suits = ["h", "c", "d", "s"]

我想返回一个没有 'c'

noclubs = ["h", "d", "s"]

有没有简单的方法可以做到这一点？

Answer 1

>>> suits = ["h","c", "d", "s"]
>>> noclubs = list(suits)
>>> noclubs.remove("c")
>>> noclubs
['h', 'd', 's']

如果您不需要单独 noclubs

>>> suits = ["h","c", "d", "s"]
>>> suits.remove("c")