“列表”对象没有属性“形状”
发布于 2021-01-29 17:54:45
如何创建一个数组到numpy数组?
def test(X, N):
[n,T] = X.shape
print "n : ", n
print "T : ", T
if __name__=="__main__":
X = [[[-9.035250067710876], [7.453250169754028], [33.34074878692627]], [[-6.63700008392334], [5.132999956607819], [31.66075038909912]], [[-5.1272499561309814], [8.251499891281128], [30.925999641418457]]]
N = 200
test(X, N)
我收到错误消息
AttributeError: 'list' object has no attribute 'shape'
所以,我想我需要将X转换为numpy数组吗?
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1 个回答
-
使用
numpy.array
在使用shape
属性。>>> import numpy as np >>> X = np.array([ ... [[-9.035250067710876], [7.453250169754028], [33.34074878692627]], ... [[-6.63700008392334], [5.132999956607819], [31.66075038909912]], ... [[-5.1272499561309814], [8.251499891281128], [30.925999641418457]] ... ]) >>> X.shape (3L, 3L, 1L)
NOTE
X.shape
为给定数组返回3个项目的元组;[n, T] = X.shape
加薪ValueError
。