如果列表中的所有==某物

Question

使用Python 2.6，有没有一种方法可以在一条语句中检查序列的所有项是否等于给定值？

[pseudocode]
my_sequence = (2,5,7,82,35)

if all the values in (type(i) for i in my_sequence) == int:
     do()

而不是说：

my_sequence = (2,5,7,82,35)
all_int = True
for i in my_sequence:
    if type(i) is not int:
        all_int = False
        break

if all_int:
    do()

Answer 1

采用：

all( type(i) is int for i in lst )

例：

In [1]: lst = range(10)
In [2]: all( type(i) is int for i in lst )
Out[2]: True
In [3]: lst.append('steve')
In [4]: all( type(i) is int for i in lst )
Out[4]: False

[编辑]。根据评论进行清洁。