在列中编写字典项的可能性

Question

我有一本字典，其中的键是元组，值是列表，例如

{('c4:7d:4f:53:24:be', 'ac:81:12:62:91:df'): [5.998999999999998,0.0013169999,   
4.0000000000000972], ('a8:5b:4f:2e:fe:09', 'de:62:ef:4e:21:de'): [7.89899999,  
0.15647999999675390, 8.764380000972, 9.200000000]}

我想将此字典以如下列格式写入csv文件：

('c4:7d:4f:53:24:be', 'ac:81:12:62:91:df')    ('a8:5b:4f:2e:fe:09', 'de:62:ef:4e:21:de')  
             5.998999999999998                      7.89899999  
             0.0013169999                           0.15647999999675390
             4.0000000000000972                     8.764380000972   
                                                    9.200000000

我知道使用代码以行格式编写同样的事情：

writer = csv.writer(open('dict.csv', 'wb'))
for key, value in mydict.items():
    writer.writerow([key, value])

我如何在列中写同样的东西？可能吗
在此先感谢，我在这里引用了CSV文档的python文档：http
:
//docs.python.org/2/library/csv.html。没有有关按列编写的信息。

Answer 1

import csv

mydict = {('c4:7d:4f:53:24:be', 'ac:81:12:62:91:df'):
          [5.998999999999998, 0.0013169999, 4.0000000000000972],
          ('a8:5b:4f:2e:fe:09', 'de:62:ef:4e:21:de'):
          [7.89899999, 0.15647999999675390, 8.764380000972, 9.200000000]}

with open('dict.csv', 'wb') as file:
    writer = csv.writer(file, delimiter='\t')
    writer.writerow(mydict.keys())
    for row in zip(*mydict.values()):
        writer.writerow(list(row))

输出文件dict.csv：

('c4:7d:4f:53:24:be', 'ac:81:12:62:91:df')  ('a8:5b:4f:2e:fe:09', 'de:62:ef:4e:21:de')
5.998999999999998   7.89899999
0.0013169999    0.1564799999967539
4.000000000000097   8.764380000972