如何使用python解析xml feed？

Question

我正在尝试解析此xml（http://www.reddit.com/r/videos/top/.rss），但遇到了麻烦。我正在尝试在每个项目中保存youtube链接，但是由于“频道”子节点而遇到麻烦。我如何达到此级别，然后才能遍历所有项目？

#reddit parse
reddit_file = urllib2.urlopen('http://www.reddit.com/r/videos/top/.rss')
#convert to string:
reddit_data = reddit_file.read()
#close file because we dont need it anymore:
reddit_file.close()

#entire feed
reddit_root = etree.fromstring(reddit_data)
channel = reddit_root.findall('{http://purl.org/dc/elements/1.1/}channel')
print channel

reddit_feed=[]
for entry in channel:   
    #get description, url, and thumbnail
    desc = #not sure how to get this

    reddit_feed.append([desc])

Answer 1

你可以试试 findall('channel/item')

import urllib2
from xml.etree import ElementTree as etree
#reddit parse
reddit_file = urllib2.urlopen('http://www.reddit.com/r/videos/top/.rss')
#convert to string:
reddit_data = reddit_file.read()
print reddit_data
#close file because we dont need it anymore:
reddit_file.close()

#entire feed
reddit_root = etree.fromstring(reddit_data)
item = reddit_root.findall('channel/item')
print item

reddit_feed=[]
for entry in item:   
    #get description, url, and thumbnail
    desc = entry.findtext('description')  
    reddit_feed.append([desc])