'int'对象在python中不可调用

发布于 2021-01-29 15:01:29

我得到了这个,我期望它在打印x.withdraw()时能打印410。

Kyle 12345 500
Traceback (most recent call last):
    File "bank.py", line 21, in <module>
        print x.withdraw()
TypeError: 'int' object is not callable

这是我的代码:

class Bank:
    def __init__(self, name, id, balance, withdraw):
        self.name = name
        self.id = id
        self.balance = balance
        self.withdraw = withdraw
    def print_info(self):
        return "%s %d %d" % (self.name, self.id, self.balance)
    def withdraw(self):
        if self.withdraw > self.balance:
            return "ERROR: Not enough funds for this transfer"
        elif self.withdraw < self.balance and self.withdraw >= 0:
            self.balance = self.balace - self.withdraw
            return self.balance
        else:
            return "Not a legitimate amount of funds"

x = Bank("Kyle", 12345, 500, 90)
print x.print_info()
print x.withdraw()

我是否需要在类本身中修复某些问题,或者我的方法调用有问题?

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1 个回答
  • 面试哥
    面试哥 2021-01-29
    为面试而生,有面试问题,就找面试哥。

    您在实例上设置具有相同名称的属性:

    self.withdraw = withdraw
    

    您正在尝试调用的是该属性,而不是方法。Python不会区分方法和属性,它们也不位于单独的命名空间中。

    为属性使用其他名称;withdrawn(退出的过去时)作为更好的属性名称浮现在脑海:

    class Bank:
        def __init__(self, name, id, balance, withdrawn):
            self.name = name
            self.id = id
            self.balance = balance
            self.withdrawn = withdrawn
        def print_info(self):
            return "%s %d %d" % (self.name, self.id, self.balance)
        def withdraw(self):
            if self.withdrawn > self.balance:
                return "ERROR: Not enough funds for this transfer"
            elif self.withdrawn < self.balance and self.withdrawn >= 0:
                self.balance = self.balance - self.withdrawn
                return self.balance
            else:
                return "Not a legitimate amount of funds"
    

    (我也纠正了一个错字;您曾balace在打算使用的位置使用过balance)。



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