Python-为什么Python无法解析此JSON数据?
发布于 2021-02-02 23:24:12
我在文件中有此JSON
:
{
"maps": [
{
"id": "blabla",
"iscategorical": "0"
},
{
"id": "blabla",
"iscategorical": "0"
}
],
"masks": [
"id": "valore"
],
"om_points": "value",
"parameters": [
"id": "valore"
]
}
我编写了以下脚本来打印所有JSON
数据:
import json
from pprint import pprint
with open('data.json') as f:
data = json.load(f)
pprint(data)
但是,该程序会引发异常:
Traceback (most recent call last):
File "<pyshell#1>", line 5, in <module>
data = json.load(f)
File "/usr/lib/python3.5/json/__init__.py", line 319, in loads
return _default_decoder.decode(s)
File "/usr/lib/python3.5/json/decoder.py", line 339, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/usr/lib/python3.5/json/decoder.py", line 355, in raw_decode
obj, end = self.scan_once(s, idx)
json.decoder.JSONDecodeError: Expecting ',' delimiter: line 13 column 13 (char 213)
如何解析JSON
并提取其值?
关注者
0
被浏览
323
1 个回答
-
你的数据不是有效的
JSON
格式。你有[]
什么时候应该拥有{}
:[]
用于JSON数组,在Python中称为list
{}
用于JSON对象,在Python中称为dict
JSON文件的外观如下:
{ "maps": [ { "id": "blabla", "iscategorical": "0" }, { "id": "blabla", "iscategorical": "0" } ], "masks": { "id": "valore" }, "om_points": "value", "parameters": { "id": "valore" } }
然后,你可以使用你的代码:
import json from pprint import pprint with open('data.json') as f: data = json.load(f) pprint(data)
有了数据,你现在还可以找到类似的值:
data["maps"][0]["id"] data["masks"]["id"] data["om_points"]
试试看,看看是否有意义。