Python-使用Spark将列转置为行
发布于 2021-02-02 23:12:31
我正在尝试将表的某些列转置为行。我正在使用Python和Spark 1.5.0。这是我的初始表:
+-----+-----+-----+-------+
| A |col_1|col_2|col_...|
+-----+-------------------+
| 1 | 0.0| 0.6| ... |
| 2 | 0.6| 0.7| ... |
| 3 | 0.5| 0.9| ... |
| ...| ...| ...| ... |
我想要这样的东西:
+-----+--------+-----------+
| A | col_id | col_value |
+-----+--------+-----------+
| 1 | col_1| 0.0|
| 1 | col_2| 0.6|
| ...| ...| ...|
| 2 | col_1| 0.6|
| 2 | col_2| 0.7|
| ...| ...| ...|
| 3 | col_1| 0.5|
| 3 | col_2| 0.9|
| ...| ...| ...|
有人知道我能做到吗?谢谢你的帮助。
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1 个回答
-
使用基本的Spark SQL函数相对简单。
python
from pyspark.sql.functions import array, col, explode, struct, lit df = sc.parallelize([(1, 0.0, 0.6), (1, 0.6, 0.7)]).toDF(["A", "col_1", "col_2"]) def to_long(df, by): # Filter dtypes and split into column names and type description cols, dtypes = zip(*((c, t) for (c, t) in df.dtypes if c not in by)) # Spark SQL supports only homogeneous columns assert len(set(dtypes)) == 1, "All columns have to be of the same type" # Create and explode an array of (column_name, column_value) structs kvs = explode(array([ struct(lit(c).alias("key"), col(c).alias("val")) for c in cols ])).alias("kvs") return df.select(by + [kvs]).select(by + ["kvs.key", "kvs.val"]) to_long(df, ["A"])
Scala:
import org.apache.spark.sql.DataFrame import org.apache.spark.sql.functions.{array, col, explode, lit, struct} val df = Seq((1, 0.0, 0.6), (1, 0.6, 0.7)).toDF("A", "col_1", "col_2") def toLong(df: DataFrame, by: Seq[String]): DataFrame = { val (cols, types) = df.dtypes.filter{ case (c, _) => !by.contains(c)}.unzip require(types.distinct.size == 1, s"${types.distinct.toString}.length != 1") val kvs = explode(array( cols.map(c => struct(lit(c).alias("key"), col(c).alias("val"))): _* )) val byExprs = by.map(col(_)) df .select(byExprs :+ kvs.alias("_kvs"): _*) .select(byExprs ++ Seq($"_kvs.key", $"_kvs.val"): _*) } toLong(df, Seq("A"))