解析命令行参数的最佳方法?
发布于 2022-05-26 22:56:00
在 Scala 中解析命令行参数的最佳方法是什么?我个人更喜欢不需要外部 jar 的轻量级产品。
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val parser = new scopt.OptionParser[Config]("scopt") { head("scopt", "3.x") opt[Int]('f', "foo") action { (x, c) => c.copy(foo = x) } text("foo is an integer property") opt[File]('o', "out") required() valueName("<file>") action { (x, c) => c.copy(out = x) } text("out is a required file property") opt[(String, Int)]("max") action { case ((k, v), c) => c.copy(libName = k, maxCount = v) } validate { x => if (x._2 > 0) success else failure("Value <max> must be >0") } keyValueName("<libname>", "<max>") text("maximum count for <libname>") opt[Unit]("verbose") action { (_, c) => c.copy(verbose = true) } text("verbose is a flag") note("some notes.\n") help("help") text("prints this usage text") arg[File]("<file>...") unbounded() optional() action { (x, c) => c.copy(files = c.files :+ x) } text("optional unbounded args") cmd("update") action { (_, c) => c.copy(mode = "update") } text("update is a command.") children( opt[Unit]("not-keepalive") abbr("nk") action { (_, c) => c.copy(keepalive = false) } text("disable keepalive"), opt[Boolean]("xyz") action { (x, c) => c.copy(xyz = x) } text("xyz is a boolean property") ) } // parser.parse returns Option[C] parser.parse(args, Config()) map { config => // do stuff } getOrElse { // arguments are bad, usage message will have been displayed }
以上生成以下使用文本:
scopt 3.x Usage: scopt [update] [options] [<file>...] -f <value> | --foo <value> foo is an integer property -o <file> | --out <file> out is a required file property --max:<libname>=<max> maximum count for <libname> --verbose verbose is a flag some notes. --help prints this usage text <file>... optional unbounded args Command: update update is a command. -nk | --not-keepalive disable keepalive --xyz <value> xyz is a boolean property
这是我目前使用的。清洁使用没有太多的行李。(免责声明:我现在维护这个项目)