如何使用react-router重定向到另一个路由?
我正在尝试使用react-router( 版本^ 1.0.3 )重定向到另一个视图,这让我很累。
import React from 'react';
import {Router, Route, Link, RouteHandler} from 'react-router';
class HomeSection extends React.Component {
static contextTypes = {
router: PropTypes.func.isRequired
};
constructor(props, context) {
super(props, context);
}
handleClick = () => {
console.log('HERE!', this.contextTypes);
// this.context.location.transitionTo('login');
};
render() {
return (
<Grid>
<Row className="text-center">
<Col md={12} xs={12}>
<div className="input-group">
<span className="input-group-btn">
<button onClick={this.handleClick} type="button">
</button>
</span>
</div>
</Col>
</Row>
</Grid>
);
}
};
HomeSection.contextTypes = {
location() {
React.PropTypes.func.isRequired
}
}
export default HomeSection;
我所需要的只是将使用发送到’/ login’就是这样。
我能做什么 ?
控制台错误:
未捕获的ReferenceError:未定义PropTypes
用我的路线归档
// LIBRARY
/*eslint-disable no-unused-vars*/
import React from 'react';
/*eslint-enable no-unused-vars*/
import {Route, IndexRoute} from 'react-router';
// COMPONENT
import Application from './components/App/App';
import Contact from './components/ContactSection/Contact';
import HomeSection from './components/HomeSection/HomeSection';
import NotFoundSection from './components/NotFoundSection/NotFoundSection';
import TodoSection from './components/TodoSection/TodoSection';
import LoginForm from './components/LoginForm/LoginForm';
import SignupForm from './components/SignupForm/SignupForm';
export default (
<Route component={Application} path='/'>
<IndexRoute component={HomeSection} />
<Route component={HomeSection} path='home' />
<Route component={TodoSection} path='todo' />
<Route component={Contact} path='contact' />
<Route component={LoginForm} path='login' />
<Route component={SignupForm} path='signup' />
<Route component={NotFoundSection} path='*' />
</Route>
);
-
对于简单的答案,您可以使用
Link
来自的组件react- router
,而不是button
。有一些方法可以更改JS中的路由,但是似乎您在这里不需要。<span className="input-group-btn"> <Link to="/login" />Click to login</Link> </span>
要在1.0.x中以编程方式执行此操作,您需要在clickHandler函数中这样做:
this.history.pushState(null, 'login');
取自此处的升级文档
您应该通过
this.history
放置在路由处理程序组件上react- router
。如果它的子组件低于routes
定义中提到的子组件,则可能需要将其进一步传递