当使用react-router-dom中的Link时,为什么在'History'上无法执行'pushState'?

发布于 2021-01-31 22:51:32

我看过类似的帖子,但找不到答案,就我而言,我正试图通过以下方式采取行动<App />

  addExpense = (expense) => {
    console.log('Hello From AddExpenseForm');
  }

/create路线在那里我渲染<AddExpenseForm />组件

<Link to={{
  pathname: '/create',
  state: { addExpense: this.addExpense }
}}> Create Expense</Link>

链接已呈现,但是当我单击它时,控制台出现错误:

Uncaught DOMException: Failed to execute 'pushState' on 'History': function (expense) {
      console.log('Hello From addExpense');
    } could not be cloned

为什么会这样,这里的解决方法是什么?

我更新的代码:

Index.js中的路由:

const Routes = () => {
  return (
      <BrowserRouter>
        <Switch>
          <Route path="/" exact component={App} />
          <Route path="/create" exact component={AddExpenseForm}/>
          <Route path="/expense/:expenseId" name="routename" component={ExpenseDetails} />
          <Route component={NotFound} />
        </Switch>
      </BrowserRouter>
  )
}

App.js:

  addExpense = (expense = {}) => {
    console.log('Hello From AddExpenseForm');
  }

  goToNextPage = (addExpense) => {
    this.props.history.push({
      pathname: '/create',
      state: { addExpense: this.addExpense }
    });
  }

  render() {
    return (
      <div>
        <Header
        />
        <button onClick={this.goToNextPage}>Create</button>
        ...
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1 个回答
  • 面试哥
    面试哥 2021-01-31
    为面试而生,有面试问题,就找面试哥。

    首先 ,为您的addExpense函数添加一些默认值:

      addExpense = (expense = DEFAULT) => {
        console.log('Hello From addExpense');
      }
    

    然后 使用Link

    <Link to={`/ideas/${this.addExpense}`}>Create Expense​</Link>
    

    尝试以下 方法更好的方法 ):

      goToNextPage = (addExpense) => {
        this.props.history.push({
          pathname: '/create',
          state: { addExpense: addExpense }
        });
      }
    

    在next(create)组件中,使用传递的值,如下所示:

    this.props.location.state.addExpense();
    


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