作者:VB.NET开发
项目:Syste
Dim dNumber As Double
dNumber = 23.15
Try
' Returns 23
Dim iNumber As Integer
iNumber = System.Convert.ToInt32(dNumber)
Catch exp As System.OverflowException
System.Console.WriteLine("Overflow in double to int conversion.")
End Try
' Returns True
Dim bNumber As Boolean
bNumber = System.Convert.ToBoolean(dNumber)
' Returns "23.15"
Dim strNumber As String
strNumber = System.Convert.ToString(dNumber)
Try
' Returns '2'
Dim chrNumber As Char
chrNumber = System.Convert.ToChar(strNumber.Chars(1))
Catch exp As System.ArgumentNullException
System.Console.WriteLine("String is null.")
Catch exp As System.FormatException
System.Console.WriteLine("String length is greater than 1.")
End Try
' System.Console.ReadLine() returns a string and it
' must be converted.
Dim newInteger As Integer
newInteger = 0
Try
System.Console.WriteLine("Enter an integer:")
newInteger = System.Convert.ToInt32(System.Console.ReadLine())
Catch exp As System.ArgumentNullException
System.Console.WriteLine("String is null.")
Catch exp As System.FormatException
System.Console.WriteLine("String does not consist of an " + _
"optional sign followed by a series of digits.")
Catch exp As System.OverflowException
System.Console.WriteLine("Overflow in string to int conversion.")
End Try
System.Console.WriteLine("Your integer as a double is {0}", _
System.Convert.ToDouble(newInteger))
作者:VB.NET开发
项目:Syste
Module Example
Public Sub Main()
Dim baseValues() As Integer = { 2, 8, 10, 16 }
Dim value As Short = Int16.MaxValue
For Each baseValue in baseValues
Dim s As String = Convert.ToString(value, baseValue)
Dim value2 As Short = Convert.ToInt16(s, baseValue)
Console.WriteLine("{0} --> {1} (base {2}) --> {3}",
value, s, baseValue, value2)
Next
End Sub
End Module