vb System.Char.IsLetter类(方法)实例源码

Module IsLetterSample

    Sub Main()

        Dim ch8 As Char
        ch8 = "8"c

        Console.WriteLine(Char.IsLetter(ch8))                   ' Output: "False"
        Console.WriteLine(Char.IsLetter("sample string", 5))    ' Output: "True"

    End Sub

End Module

' 导入命名空间
Imports System

Public Class MainClass

   Shared Sub Main()
      Console.WriteLine("is letter: " & Char.IsLetter("aaa") )
  End Sub ' Main

End Class