python类setrecursionlimit()的实例源码

test_stealth.py 文件源码 项目:zeronet-debian 作者: bashrc 项目源码 文件源码 阅读 23 收藏 0 点赞 0 评论 0
def setUp(self):

        if sys.getrecursionlimit() < 1000:
            sys.setrecursionlimit(1000)

        self.addr = 'vJmtjxSDxNPXL4RNapp9ARdqKz3uJyf1EDGjr1Fgqs9c8mYsVH82h8wvnA4i5rtJ57mr3kor1EVJrd4e5upACJd588xe52yXtzumxj'
        self.scan_pub = '025e58a31122b38c86abc119b9379fe247410aee87a533f9c07b189aef6c3c1f52'
        self.scan_priv = '3e49e7257cb31db997edb1cf8299af0f37e2663e2260e4b8033e49d39a6d02f2'
        self.spend_pub = '03616562c98e7d7b74be409a787cec3a912122f3fb331a9bee9b0b73ce7b9f50af'
        self.spend_priv = 'aa3db0cfb3edc94de4d10f873f8190843f2a17484f6021a95a7742302c744748'
        self.ephem_pub = '03403d306ec35238384c7e340393335f9bc9bb4a2e574eb4e419452c4ea19f14b0'
        self.ephem_priv = '9e63abaf8dcd5ea3919e6de0b6c544e00bf51bf92496113a01d6e369944dc091'
        self.shared_secret = 'a4047ee231f4121e3a99a3a3378542e34a384b865a9917789920e1f13ffd91c6'
        self.pay_pub = '02726112ad39cb6bf848b1b1ef30b88e35286bf99f746c2be575f96c0e02a9357c'
        self.pay_priv = '4e422fb1e5e1db6c1f6ab32a7706d368ceb385e7fab098e633c5c5949c3b97cd'

        self.testnet_addr = 'waPUuLLykSnY3itzf1AyrQZm42F7KyB7SR5zpfqmnzPXWhx9kXLzV3EcyqzDdpTwngiyCCMUqztS9S1d7XJs3JMt3MsHPDpBCudvx9'
__init__.py 文件源码 项目:CSB 作者: csb-toolbox 项目源码 文件源码 阅读 28 收藏 0 点赞 0 评论 0
def deepcopy(obj, recursion=100000):
    """
    Perform a deep copy of obj using cPickle. Faster than copy.deepcopy()
    for large objects.

    @param obj: the object to copy
    @return: a deep copy of obj
    @param recursion: maximum recursion limit
    @type recursion: int
    """
    from csb.io import Pickle

    current = sys.getrecursionlimit()
    sys.setrecursionlimit(recursion)

    tmp = Pickle.dumps(obj, Pickle.HIGHEST_PROTOCOL)
    copy = Pickle.loads(tmp)

    sys.setrecursionlimit(current)
    return copy
test_sys.py 文件源码 项目:zippy 作者: securesystemslab 项目源码 文件源码 阅读 30 收藏 0 点赞 0 评论 0
def test_recursionlimit_recovery(self):
        # NOTE: this test is slightly fragile in that it depends on the current
        # recursion count when executing the test being low enough so as to
        # trigger the recursion recovery detection in the _Py_MakeEndRecCheck
        # macro (see ceval.h).
        oldlimit = sys.getrecursionlimit()
        def f():
            f()
        try:
            for i in (50, 1000):
                # Issue #5392: stack overflow after hitting recursion limit twice
                sys.setrecursionlimit(i)
                self.assertRaises(RuntimeError, f)
                self.assertRaises(RuntimeError, f)
        finally:
            sys.setrecursionlimit(oldlimit)
test_sys.py 文件源码 项目:zippy 作者: securesystemslab 项目源码 文件源码 阅读 30 收藏 0 点赞 0 评论 0
def test_recursionlimit_fatalerror(self):
        # A fatal error occurs if a second recursion limit is hit when recovering
        # from a first one.
        if os.name == "nt":
            raise unittest.SkipTest(
                "under Windows, test would generate a spurious crash dialog")
        code = textwrap.dedent("""
            import sys

            def f():
                try:
                    f()
                except RuntimeError:
                    f()

            sys.setrecursionlimit(%d)
            f()""")
        for i in (50, 1000):
            sub = subprocess.Popen([sys.executable, '-c', code % i],
                stderr=subprocess.PIPE)
            err = sub.communicate()[1]
            self.assertTrue(sub.returncode, sub.returncode)
            self.assertTrue(
                b"Fatal Python error: Cannot recover from stack overflow" in err,
                err)
models.py 文件源码 项目:incubator-airflow-old 作者: apache 项目源码 文件源码 阅读 27 收藏 0 点赞 0 评论 0
def __deepcopy__(self, memo):
        """
        Hack sorting double chained task lists by task_id to avoid hitting
        max_depth on deepcopy operations.
        """
        sys.setrecursionlimit(5000)  # TODO fix this in a better way
        cls = self.__class__
        result = cls.__new__(cls)
        memo[id(self)] = result

        for k, v in list(self.__dict__.items()):
            if k not in ('user_defined_macros', 'user_defined_filters', 'params'):
                setattr(result, k, copy.deepcopy(v, memo))
        result.params = self.params
        if hasattr(self, 'user_defined_macros'):
            result.user_defined_macros = self.user_defined_macros
        if hasattr(self, 'user_defined_filters'):
            result.user_defined_filters = self.user_defined_filters
        return result
test_sys.py 文件源码 项目:oil 作者: oilshell 项目源码 文件源码 阅读 31 收藏 0 点赞 0 评论 0
def test_recursionlimit(self):
        self.assertRaises(TypeError, sys.getrecursionlimit, 42)
        oldlimit = sys.getrecursionlimit()
        self.assertRaises(TypeError, sys.setrecursionlimit)
        self.assertRaises(ValueError, sys.setrecursionlimit, -42)
        sys.setrecursionlimit(10000)
        self.assertEqual(sys.getrecursionlimit(), 10000)
        sys.setrecursionlimit(oldlimit)

        self.assertRaises(OverflowError, sys.setrecursionlimit, 1 << 31)
        try:
            sys.setrecursionlimit((1 << 31) - 5)
            try:
                # issue13546: isinstance(e, ValueError) used to fail
                # when the recursion limit is close to 1<<31
                raise ValueError()
            except ValueError, e:
                pass
        finally:
            sys.setrecursionlimit(oldlimit)
find_recursionlimit.py 文件源码 项目:oil 作者: oilshell 项目源码 文件源码 阅读 23 收藏 0 点赞 0 评论 0
def check_limit(n, test_func_name):
    sys.setrecursionlimit(n)
    if test_func_name.startswith("test_"):
        print test_func_name[5:]
    else:
        print test_func_name
    test_func = globals()[test_func_name]
    try:
        test_func()
    # AttributeError can be raised because of the way e.g. PyDict_GetItem()
    # silences all exceptions and returns NULL, which is usually interpreted
    # as "missing attribute".
    except (RuntimeError, AttributeError):
        pass
    else:
        print "Yikes!"
test_sys.py 文件源码 项目:python2-tracer 作者: extremecoders-re 项目源码 文件源码 阅读 25 收藏 0 点赞 0 评论 0
def test_recursionlimit(self):
        self.assertRaises(TypeError, sys.getrecursionlimit, 42)
        oldlimit = sys.getrecursionlimit()
        self.assertRaises(TypeError, sys.setrecursionlimit)
        self.assertRaises(ValueError, sys.setrecursionlimit, -42)
        sys.setrecursionlimit(10000)
        self.assertEqual(sys.getrecursionlimit(), 10000)
        sys.setrecursionlimit(oldlimit)

        self.assertRaises(OverflowError, sys.setrecursionlimit, 1 << 31)
        try:
            sys.setrecursionlimit((1 << 31) - 5)
            try:
                # issue13546: isinstance(e, ValueError) used to fail
                # when the recursion limit is close to 1<<31
                raise ValueError()
            except ValueError, e:
                pass
        finally:
            sys.setrecursionlimit(oldlimit)
find_recursionlimit.py 文件源码 项目:python2-tracer 作者: extremecoders-re 项目源码 文件源码 阅读 25 收藏 0 点赞 0 评论 0
def check_limit(n, test_func_name):
    sys.setrecursionlimit(n)
    if test_func_name.startswith("test_"):
        print test_func_name[5:]
    else:
        print test_func_name
    test_func = globals()[test_func_name]
    try:
        test_func()
    # AttributeError can be raised because of the way e.g. PyDict_GetItem()
    # silences all exceptions and returns NULL, which is usually interpreted
    # as "missing attribute".
    except (RuntimeError, AttributeError):
        pass
    else:
        print "Yikes!"
index_generator.py 文件源码 项目:azure-shell 作者: yokawasa 项目源码 文件源码 阅读 29 收藏 0 点赞 0 评论 0
def populate_group_command_tree(group, groups_map,cmds_map):
    ## Inrease the limit just in case recursive func calling use up recursionlimit
    #import sys
    #sys.setrecursionlimit(10000)
    subgroups = []
    for subgroup_name in group['subgroups']:
        if groups_map.has_key(subgroup_name):
            subgroup = groups_map[subgroup_name]
            populate_group_command_tree(subgroup, groups_map, cmds_map)
            subgroups.append(subgroup)
    group['subgroups']=subgroups
    cmd_list = []
    for cmd_name in group['commands']:
        if cmds_map.has_key(cmd_name):
            cmd_list.append(cmds_map[cmd_name])
    group['commands']=cmd_list
test_sys.py 文件源码 项目:web_ctp 作者: molebot 项目源码 文件源码 阅读 35 收藏 0 点赞 0 评论 0
def test_recursionlimit_recovery(self):
        # NOTE: this test is slightly fragile in that it depends on the current
        # recursion count when executing the test being low enough so as to
        # trigger the recursion recovery detection in the _Py_MakeEndRecCheck
        # macro (see ceval.h).
        oldlimit = sys.getrecursionlimit()
        def f():
            f()
        try:
            for i in (50, 1000):
                # Issue #5392: stack overflow after hitting recursion limit twice
                sys.setrecursionlimit(i)
                self.assertRaises(RuntimeError, f)
                self.assertRaises(RuntimeError, f)
        finally:
            sys.setrecursionlimit(oldlimit)
test_sys.py 文件源码 项目:web_ctp 作者: molebot 项目源码 文件源码 阅读 32 收藏 0 点赞 0 评论 0
def test_recursionlimit_fatalerror(self):
        # A fatal error occurs if a second recursion limit is hit when recovering
        # from a first one.
        code = textwrap.dedent("""
            import sys

            def f():
                try:
                    f()
                except RuntimeError:
                    f()

            sys.setrecursionlimit(%d)
            f()""")
        with test.support.suppress_crash_popup():
            for i in (50, 1000):
                sub = subprocess.Popen([sys.executable, '-c', code % i],
                    stderr=subprocess.PIPE)
                err = sub.communicate()[1]
                self.assertTrue(sub.returncode, sub.returncode)
                self.assertIn(
                    b"Fatal Python error: Cannot recover from stack overflow",
                    err)
test_basic_data_structures.py 文件源码 项目:AlgorithmicToolbox 作者: chaicko 项目源码 文件源码 阅读 23 收藏 0 点赞 0 评论 0
def test_worst_case(self):
        sys.setrecursionlimit(10 ** 7)  # max depth of recursion
        resource.setrlimit(resource.RLIMIT_STACK,
                           (resource.RLIM_INFINITY, resource.RLIM_INFINITY))
        #  Worst case is a tree with one child per node, that is, a list
        test_input = [-1 if x == 0 else x - 1 for x in range(10 ** 5)]
        tree = tree_height.TreeHeight(len(test_input), test_input)
        assert len(test_input) == tree.compute_height()

        # def test_provided_input_data(self):
        #     files_wildcard = os.path.dirname(__file__) + "/tree_height_test_input/*"
        #     files = glob.glob(files_wildcard)
        #     for file in files:
        #         with open(file) as f:
        #             size = f.readline()
        #             parent = f.readline()
        #             test_input = [int(x) for x in parent.split()]
        #             tree = tree_height.TreeHeight(len(test_input), test_input)
wienerAttack.py 文件源码 项目:CTF-Crypto 作者: ValarDragon 项目源码 文件源码 阅读 28 收藏 0 点赞 0 评论 0
def __init__(self, n, e):
        self.d = None
        self.p = None
        self.q = None
        sys.setrecursionlimit(100000)
        frac = self.rational_to_contfrac(e, n)
        convergents = self.convergents_from_contfrac(frac)

        for (k,d) in convergents:
            if k!=0 and (e*d-1)%k == 0:
                phi = (e*d-1)//k
                s = n - phi + 1
                discr = s*s - 4*n
                if(discr>=0):
                    t = self.is_perfect_square(discr)
                    if t!=-1 and (s+t)%2==0:
                        self.d = d
                        x = Symbol('x')
                        roots = solve(x**2 - s*x + n, x)
                        if len(roots) == 2:
                            self.p = roots[0]
                            self.q = roots[1]
                        break
fymodule.py 文件源码 项目:fython 作者: nicolasessisbreton 项目源码 文件源码 阅读 25 收藏 0 点赞 0 评论 0
def save(s):
        # increasing recursion depth to avoid pickle: maximum recursion depth error, see:
        #   http://stackoverflow.com/q/2134706/1030312

        current_limit = sys.getrecursionlimit()

        if current_limit < fypickling_recursion_limit:
            sys.setrecursionlimit(fypickling_recursion_limit)   

        dump(
            s, 
            open(s.url.pickle, 'wb'), 
            protocol = HIGHEST_PROTOCOL, 
        )


        if current_limit < fypickling_recursion_limit:
            sys.setrecursionlimit(current_limit)
test_sys.py 文件源码 项目:pefile.pypy 作者: cloudtracer 项目源码 文件源码 阅读 29 收藏 0 点赞 0 评论 0
def test_recursionlimit(self):
        self.assertRaises(TypeError, sys.getrecursionlimit, 42)
        oldlimit = sys.getrecursionlimit()
        self.assertRaises(TypeError, sys.setrecursionlimit)
        self.assertRaises(ValueError, sys.setrecursionlimit, -42)
        sys.setrecursionlimit(10000)
        self.assertEqual(sys.getrecursionlimit(), 10000)
        sys.setrecursionlimit(oldlimit)

        self.assertRaises(OverflowError, sys.setrecursionlimit, 1 << 31)
        try:
            sys.setrecursionlimit((1 << 31) - 5)
            try:
                # issue13546: isinstance(e, ValueError) used to fail
                # when the recursion limit is close to 1<<31
                raise ValueError()
            except ValueError, e:
                pass
        finally:
            sys.setrecursionlimit(oldlimit)
test_sys.py 文件源码 项目:ouroboros 作者: pybee 项目源码 文件源码 阅读 29 收藏 0 点赞 0 评论 0
def test_recursionlimit_recovery(self):
        if hasattr(sys, 'gettrace') and sys.gettrace():
            self.skipTest('fatal error if run with a trace function')

        # NOTE: this test is slightly fragile in that it depends on the current
        # recursion count when executing the test being low enough so as to
        # trigger the recursion recovery detection in the _Py_MakeEndRecCheck
        # macro (see ceval.h).
        oldlimit = sys.getrecursionlimit()
        def f():
            f()
        try:
            for i in (50, 1000):
                # Issue #5392: stack overflow after hitting recursion limit twice
                sys.setrecursionlimit(i)
                self.assertRaises(RuntimeError, f)
                self.assertRaises(RuntimeError, f)
        finally:
            sys.setrecursionlimit(oldlimit)
test_sys.py 文件源码 项目:ouroboros 作者: pybee 项目源码 文件源码 阅读 30 收藏 0 点赞 0 评论 0
def test_recursionlimit_fatalerror(self):
        # A fatal error occurs if a second recursion limit is hit when recovering
        # from a first one.
        code = textwrap.dedent("""
            import sys

            def f():
                try:
                    f()
                except RuntimeError:
                    f()

            sys.setrecursionlimit(%d)
            f()""")
        with test.support.SuppressCrashReport():
            for i in (50, 1000):
                sub = subprocess.Popen([sys.executable, '-c', code % i],
                    stderr=subprocess.PIPE)
                err = sub.communicate()[1]
                self.assertTrue(sub.returncode, sub.returncode)
                self.assertIn(
                    b"Fatal Python error: Cannot recover from stack overflow",
                    err)
test_sys.py 文件源码 项目:ndk-python 作者: gittor 项目源码 文件源码 阅读 25 收藏 0 点赞 0 评论 0
def test_recursionlimit(self):
        self.assertRaises(TypeError, sys.getrecursionlimit, 42)
        oldlimit = sys.getrecursionlimit()
        self.assertRaises(TypeError, sys.setrecursionlimit)
        self.assertRaises(ValueError, sys.setrecursionlimit, -42)
        sys.setrecursionlimit(10000)
        self.assertEqual(sys.getrecursionlimit(), 10000)
        sys.setrecursionlimit(oldlimit)

        self.assertRaises(OverflowError, sys.setrecursionlimit, 1 << 31)
        try:
            sys.setrecursionlimit((1 << 31) - 5)
            try:
                # issue13546: isinstance(e, ValueError) used to fail
                # when the recursion limit is close to 1<<31
                raise ValueError()
            except ValueError, e:
                pass
        finally:
            sys.setrecursionlimit(oldlimit)
models.py 文件源码 项目:airflow 作者: apache-airflow 项目源码 文件源码 阅读 27 收藏 0 点赞 0 评论 0
def __deepcopy__(self, memo):
        """
        Hack sorting double chained task lists by task_id to avoid hitting
        max_depth on deepcopy operations.
        """
        sys.setrecursionlimit(5000)  # TODO fix this in a better way
        cls = self.__class__
        result = cls.__new__(cls)
        memo[id(self)] = result

        for k, v in list(self.__dict__.items()):
            if k not in ('user_defined_macros', 'params'):
                setattr(result, k, copy.deepcopy(v, memo))
        result.params = self.params
        if hasattr(self, 'user_defined_macros'):
            result.user_defined_macros = self.user_defined_macros
        return result
test_script.py 文件源码 项目:zenchmarks 作者: squeaky-pl 项目源码 文件源码 阅读 34 收藏 0 点赞 0 评论 0
def test_getWorkerArguments(self):
        """
        C{_getWorkerArguments} discards options like C{random} as they only
        matter in the manager, and forwards options like C{recursionlimit} or
        C{disablegc}.
        """
        self.addCleanup(sys.setrecursionlimit, sys.getrecursionlimit())
        if gc.isenabled():
            self.addCleanup(gc.enable)

        self.options.parseOptions(["--recursionlimit", "2000", "--random",
                                   "4", "--disablegc"])
        args = self.options._getWorkerArguments()
        self.assertIn("--disablegc", args)
        args.remove("--disablegc")
        self.assertEqual(["--recursionlimit", "2000"], args)
test_sys.py 文件源码 项目:kbe_server 作者: xiaohaoppy 项目源码 文件源码 阅读 27 收藏 0 点赞 0 评论 0
def test_recursionlimit_recovery(self):
        # NOTE: this test is slightly fragile in that it depends on the current
        # recursion count when executing the test being low enough so as to
        # trigger the recursion recovery detection in the _Py_MakeEndRecCheck
        # macro (see ceval.h).
        oldlimit = sys.getrecursionlimit()
        def f():
            f()
        try:
            for i in (50, 1000):
                # Issue #5392: stack overflow after hitting recursion limit twice
                sys.setrecursionlimit(i)
                self.assertRaises(RuntimeError, f)
                self.assertRaises(RuntimeError, f)
        finally:
            sys.setrecursionlimit(oldlimit)
test_sys.py 文件源码 项目:kbe_server 作者: xiaohaoppy 项目源码 文件源码 阅读 30 收藏 0 点赞 0 评论 0
def test_recursionlimit_fatalerror(self):
        # A fatal error occurs if a second recursion limit is hit when recovering
        # from a first one.
        code = textwrap.dedent("""
            import sys

            def f():
                try:
                    f()
                except RuntimeError:
                    f()

            sys.setrecursionlimit(%d)
            f()""")
        with test.support.SuppressCrashReport():
            for i in (50, 1000):
                sub = subprocess.Popen([sys.executable, '-c', code % i],
                    stderr=subprocess.PIPE)
                err = sub.communicate()[1]
                self.assertTrue(sub.returncode, sub.returncode)
                self.assertIn(
                    b"Fatal Python error: Cannot recover from stack overflow",
                    err)
45.py 文件源码 项目:Matasano-Crypto 作者: james727 项目源码 文件源码 阅读 25 收藏 0 点赞 0 评论 0
def test_g_zero():
    # recursion limit :(
    sys.setrecursionlimit(2000)

    # generate signature
    m = "hello, world"
    h = int(sha1_hexdigest(m), 16)
    S = DSA_signer(g = 0)
    r, s = S.DSA_sign(h)

    # verify signature
    V = DSA_verifier(g = 0)
    print V.verify(S, r, s, h)

    forged_signature = "omgwtfbbq"
    h = int(sha1_hexdigest(forged_signature), 16)
    print V.verify(S, r, s, h)
read_write.py 文件源码 项目:visual_turing_test-tutorial 作者: mateuszmalinowski 项目源码 文件源码 阅读 27 收藏 0 点赞 0 评论 0
def pickle_model(
        path, 
        model, 
        word2index_x,
        word2index_y,
        index2word_x,
        index2word_y):
    import sys
    import cPickle as pickle
    modifier=10
    tmp = sys.getrecursionlimit()
    sys.setrecursionlimit(tmp*modifier)
    with open(path, 'wb') as f:
        p_dict = {'model':model,
                'word2index_x':word2index_x,
                'word2index_y':word2index_y,
                'index2word_x':index2word_x,
                'index2word_y':index2word_y}
        pickle.dump(p_dict, f, protocol=2)
    sys.setrecursionlimit(tmp)
exceptionHandling.py 文件源码 项目:NeoAnalysis 作者: neoanalysis 项目源码 文件源码 阅读 26 收藏 0 点赞 0 评论 0
def __call__(self, *args):
        ## Start by extending recursion depth just a bit. 
        ## If the error we are catching is due to recursion, we don't want to generate another one here.
        recursionLimit = sys.getrecursionlimit()
        try:
            sys.setrecursionlimit(recursionLimit+100)


            ## call original exception handler first (prints exception)
            global original_excepthook, callbacks, clear_tracebacks
            try:
                print("===== %s =====" % str(time.strftime("%Y.%m.%d %H:%m:%S", time.localtime(time.time()))))
            except Exception:
                sys.stderr.write("Warning: stdout is broken! Falling back to stderr.\n")
                sys.stdout = sys.stderr

            ret = original_excepthook(*args)

            for cb in callbacks:
                try:
                    cb(*args)
                except Exception:
                    print("   --------------------------------------------------------------")
                    print("      Error occurred during exception callback %s" % str(cb))
                    print("   --------------------------------------------------------------")
                    traceback.print_exception(*sys.exc_info())


            ## Clear long-term storage of last traceback to prevent memory-hogging.
            ## (If an exception occurs while a lot of data is present on the stack, 
            ## such as when loading large files, the data would ordinarily be kept
            ## until the next exception occurs. We would rather release this memory 
            ## as soon as possible.)
            if clear_tracebacks is True:
                sys.last_traceback = None

        finally:
            sys.setrecursionlimit(recursionLimit)
exceptionHandling.py 文件源码 项目:NeoAnalysis 作者: neoanalysis 项目源码 文件源码 阅读 28 收藏 0 点赞 0 评论 0
def __call__(self, *args):
        ## Start by extending recursion depth just a bit. 
        ## If the error we are catching is due to recursion, we don't want to generate another one here.
        recursionLimit = sys.getrecursionlimit()
        try:
            sys.setrecursionlimit(recursionLimit+100)


            ## call original exception handler first (prints exception)
            global original_excepthook, callbacks, clear_tracebacks
            try:
                print("===== %s =====" % str(time.strftime("%Y.%m.%d %H:%m:%S", time.localtime(time.time()))))
            except Exception:
                sys.stderr.write("Warning: stdout is broken! Falling back to stderr.\n")
                sys.stdout = sys.stderr

            ret = original_excepthook(*args)

            for cb in callbacks:
                try:
                    cb(*args)
                except Exception:
                    print("   --------------------------------------------------------------")
                    print("      Error occurred during exception callback %s" % str(cb))
                    print("   --------------------------------------------------------------")
                    traceback.print_exception(*sys.exc_info())


            ## Clear long-term storage of last traceback to prevent memory-hogging.
            ## (If an exception occurs while a lot of data is present on the stack, 
            ## such as when loading large files, the data would ordinarily be kept
            ## until the next exception occurs. We would rather release this memory 
            ## as soon as possible.)
            if clear_tracebacks is True:
                sys.last_traceback = None

        finally:
            sys.setrecursionlimit(recursionLimit)
bsp_tree.py 文件源码 项目:Blender-WMO-import-export-scripts 作者: WowDevTools 项目源码 文件源码 阅读 24 收藏 0 点赞 0 评论 0
def GenerateBSP(self, vertices, indices, max_face_count):
        resurs_limit = sys.getrecursionlimit()
        sys.setrecursionlimit(100000)

        faces = []
        for iFace in range(len(indices) // 3):
            faces.append(iFace)

        box = calculate_bounding_box(vertices)
        self.add_node(box, faces, vertices, indices, max_face_count)

        sys.setrecursionlimit(resurs_limit)
trial.py 文件源码 项目:hostapd-mana 作者: adde88 项目源码 文件源码 阅读 30 收藏 0 点赞 0 评论 0
def opt_recursionlimit(self, arg):
        """see sys.setrecursionlimit()"""
        try:
            sys.setrecursionlimit(int(arg))
        except (TypeError, ValueError):
            raise usage.UsageError(
                "argument to recursionlimit must be an integer")
convnet.py 文件源码 项目:cav_gcnn 作者: myinxd 项目源码 文件源码 阅读 27 收藏 0 点赞 0 评论 0
def cnn_save(self, savepath='cnn.pkl'):
        """Save the trained network

        input
        =====
        savepath: str
            Path of the net to be saved
        """
        import sys
        sys.setrecursionlimit(1000000)
        import pickle
        fp = open(savepath, 'wb')
        # write
        pickle.dump(self.net, fp)
        fp.close()


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