python类lu_solve()的实例源码

def solve_G(self, b):
    """Solve ``Gx=b`` where ``G`` is the Gram matrix of the GP.

    Uses the internally-stored LU decomposition of ``G`` computed in
    ``gp.update()``."""

    assert self.ready
    return linalg.lu_solve((self.LU, self.LU_piv), b, check_finite=True)

def lu_solve_ATAI(A, rho, b, lu, piv):
    r"""
    Solve the linear system :math:`(A^T A + \rho I)\mathbf{x} = \mathbf{b}`
    or :math:`(A^T A + \rho I)X = B` using :func:`scipy.linalg.lu_solve`.

    Parameters
    ----------
    A : array_like
      Matrix :math:`A`
    rho : float
      Scalar :math:`\rho`
    b : array_like
      Vector :math:`\mathbf{b}` or matrix :math:`B`
    lu : array_like
      Matrix containing U in its upper triangle, and L in its lower triangle,
      as returned by :func:`scipy.linalg.lu_factor`
    piv : array_like
      Pivot indices representing the permutation matrix P, as returned by
      :func:`scipy.linalg.lu_factor`

    Returns
    -------
    x : ndarray
      Solution to the linear system.
    """

    N, M = A.shape
    if N >= M:
        x = linalg.lu_solve((lu, piv), b)
    else:
        x = (b - A.T.dot(linalg.lu_solve((lu, piv), A.dot(b), 1))) / rho
    return x

def lu_solve_AATI(A, rho, b, lu, piv):
    r"""
    Solve the linear system :math:`(A A^T + \rho I)\mathbf{x} = \mathbf{b}`
    or :math:`(A A^T + \rho I)X = B` using :func:`scipy.linalg.lu_solve`.

    Parameters
    ----------
    A : array_like
      Matrix :math:`A`
    rho : float
      Scalar :math:`\rho`
    b : array_like
      Vector :math:`\mathbf{b}` or matrix :math:`B`
    lu : array_like
      Matrix containing U in its upper triangle, and L in its lower triangle,
      as returned by :func:`scipy.linalg.lu_factor`
    piv : array_like
      Pivot indices representing the permutation matrix P, as returned by
      :func:`scipy.linalg.lu_factor`

    Returns
    -------
    x : ndarray
      Solution to the linear system.
    """

    N, M = A.shape
    if N >= M:
        x = (b - linalg.lu_solve((lu, piv), b.dot(A).T).T.dot(A.T)) / rho
    else:
        x = linalg.lu_solve((lu, piv), b.T).T
    return x

def solve(self, rhs):
        """Solve with the system matrix

        Args:
            rhs: Right hand side in system

        Returns:
            solution to M*x = rhs
        """
        self.update()
        return la.lu_solve(self.lupiv, rhs)

def mysolve(LU, b):
    if isinstance(LU, SuperLU):
        return LU.solve(b)
    else:
        return lu_solve(LU, b)    

###############################################################################
# Solve via full system
###############################################################################

def solve_nonlinear(self, inputs, outputs):
        """
        Use numpy to solve Ax=b for x.

        Parameters
        ----------
        inputs : Vector
            unscaled, dimensional input variables read via inputs[key]
        outputs : Vector
            unscaled, dimensional output variables read via outputs[key]
        """
        # lu factorization for use with solve_linear
        self._lup = linalg.lu_factor(inputs['A'])
        outputs['x'] = linalg.lu_solve(self._lup, inputs['b'])

def solve_linear(self, d_outputs, d_residuals, mode):
        r"""
        Back-substitution to solve the derivatives of the linear system.

        If mode is:
            'fwd': d_residuals \|-> d_outputs

            'rev': d_outputs \|-> d_residuals

        Parameters
        ----------
        d_outputs : Vector
            unscaled, dimensional quantities read via d_outputs[key]
        d_residuals : Vector
            unscaled, dimensional quantities read via d_residuals[key]
        mode : str
            either 'fwd' or 'rev'
        """
        if mode == 'fwd':
            sol_vec, rhs_vec = d_outputs, d_residuals
            t = 0
        else:
            sol_vec, rhs_vec = d_residuals, d_outputs
            t = 1

        # print("foobar", rhs_vec['x'])
        sol_vec['x'] = linalg.lu_solve(self._lup, rhs_vec['x'], trans=t)

def solve_nonlinear(self, inputs, outputs):
        force_vector = np.concatenate([self.metadata['force_vector'], np.zeros(2)])

        self.lu = lu_factor(inputs['K'])

        outputs['d'] = lu_solve(self.lu, force_vector)

def solve_linear(self, d_outputs, d_residuals, mode):
        if mode == 'fwd':
            d_outputs['d'] = lu_solve(self.lu, d_residuals['d'], trans=0)
        else:
            d_residuals['d'] = lu_solve(self.lu, d_outputs['d'], trans=1)

def _matvec(self, x):
        return lu_solve(self.M_lu, x)