python类trans_36()的实例源码

transport.py 文件源码 项目:zenchmarks 作者: squeaky-pl 项目源码 文件源码 阅读 24 收藏 0 点赞 0 评论 0
def _getMAC(self, mac, key):
        """
        Gets a 4-tuple representing the message authentication code.
        (<hash module>, <inner hash value>, <outer hash value>,
        <digest size>)

        @type mac: L{bytes}
        @param mac: a key mapping into macMap

        @type key: L{bytes}
        @param key: the MAC key.

        @rtype: L{bytes}
        @return: The MAC components.
        """
        mod = self.macMap[mac]
        if not mod:
            return (None, b'', b'', 0)

        # With stdlib we can only get attributes fron an instantiated object.
        hashObject = mod()
        digestSize = hashObject.digest_size
        blockSize = hashObject.block_size

        # Truncation here appears to contravene RFC 2104, section 2.  However,
        # implementing the hashing behavior prescribed by the RFC breaks
        # interoperability with OpenSSH (at least version 5.5p1).
        key = key[:digestSize] + (b'\x00' * (blockSize - digestSize))
        i = key.translate(hmac.trans_36)
        o = key.translate(hmac.trans_5C)
        result = _MACParams((mod, i, o, digestSize))
        result.key = key
        return result
crypto.py 文件源码 项目:CodingDojo 作者: ComputerSocietyUNB 项目源码 文件源码 阅读 24 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation. Look in
        django.contrib.auth.hashers for the present default, it is lower than
        the recommended 100,000 because of the performance difference between
        this and an optimized implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha256
        password = force_bytes(password)
        salt = force_bytes(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        l = -(-dklen // hlen)
        r = dklen - (l - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in range(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in range(1, l)]
        return b''.join(T) + F(l)[:r]
pbkdf2.py 文件源码 项目:MCSManager-fsmodule 作者: Suwings 项目源码 文件源码 阅读 30 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha1
        password = bytes_(password)
        salt = bytes_(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        l = -(-dklen // hlen)
        r = dklen - (l - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in xrange_(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in xrange_(1, l)]
        return b''.join(T) + F(l)[:r]
pbkdf2.py 文件源码 项目:python-group-proj 作者: Sharcee 项目源码 文件源码 阅读 22 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha1
        password = bytes_(password)
        salt = bytes_(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        l = -(-dklen // hlen)
        r = dklen - (l - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in xrange_(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in xrange_(1, l)]
        return b''.join(T) + F(l)[:r]
crypto.py 文件源码 项目:lifesoundtrack 作者: MTG 项目源码 文件源码 阅读 33 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation. Look in
        django.contrib.auth.hashers for the present default, it is lower than
        the recommended 100,000 because of the performance difference between
        this and an optimized implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha256
        password = force_bytes(password)
        salt = force_bytes(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        l = -(-dklen // hlen)
        r = dklen - (l - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in range(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in range(1, l)]
        return b''.join(T) + F(l)[:r]
crypto.py 文件源码 项目:liberator 作者: libscie 项目源码 文件源码 阅读 31 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation. Look in
        django.contrib.auth.hashers for the present default, it is lower than
        the recommended 100,000 because of the performance difference between
        this and an optimized implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha256
        password = force_bytes(password)
        salt = force_bytes(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        L = -(-dklen // hlen)
        r = dklen - (L - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in range(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in range(1, L)]
        return b''.join(T) + F(L)[:r]
crypto.py 文件源码 项目:djanoDoc 作者: JustinChavez 项目源码 文件源码 阅读 26 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation. Look in
        django.contrib.auth.hashers for the present default, it is lower than
        the recommended 100,000 because of the performance difference between
        this and an optimized implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha256
        password = force_bytes(password)
        salt = force_bytes(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        l = -(-dklen // hlen)
        r = dklen - (l - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in range(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in range(1, l)]
        return b''.join(T) + F(l)[:r]
crypto.py 文件源码 项目:django-next-train 作者: bitpixdigital 项目源码 文件源码 阅读 33 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation. Look in
        django.contrib.auth.hashers for the present default, it is lower than
        the recommended 100,000 because of the performance difference between
        this and an optimized implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha256
        password = force_bytes(password)
        salt = force_bytes(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        l = -(-dklen // hlen)
        r = dklen - (l - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in range(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in range(1, l)]
        return b''.join(T) + F(l)[:r]
crypto.py 文件源码 项目:django-wechat-api 作者: crazy-canux 项目源码 文件源码 阅读 24 收藏 0 点赞 0 评论 0
def pbkdf2(password, salt, iterations, dklen=0, digest=None):
        """
        Implements PBKDF2 as defined in RFC 2898, section 5.2

        HMAC+SHA256 is used as the default pseudo random function.

        As of 2014, 100,000 iterations was the recommended default which took
        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
        probably the bare minimum for security given 1000 iterations was
        recommended in 2001. This code is very well optimized for CPython and
        is about five times slower than OpenSSL's implementation. Look in
        django.contrib.auth.hashers for the present default, it is lower than
        the recommended 100,000 because of the performance difference between
        this and an optimized implementation.
        """
        assert iterations > 0
        if not digest:
            digest = hashlib.sha256
        password = force_bytes(password)
        salt = force_bytes(salt)
        hlen = digest().digest_size
        if not dklen:
            dklen = hlen
        if dklen > (2 ** 32 - 1) * hlen:
            raise OverflowError('dklen too big')
        l = -(-dklen // hlen)
        r = dklen - (l - 1) * hlen

        hex_format_string = "%%0%ix" % (hlen * 2)

        inner, outer = digest(), digest()
        if len(password) > inner.block_size:
            password = digest(password).digest()
        password += b'\x00' * (inner.block_size - len(password))
        inner.update(password.translate(hmac.trans_36))
        outer.update(password.translate(hmac.trans_5C))

        def F(i):
            u = salt + struct.pack(b'>I', i)
            result = 0
            for j in range(int(iterations)):
                dig1, dig2 = inner.copy(), outer.copy()
                dig1.update(u)
                dig2.update(dig1.digest())
                u = dig2.digest()
                result ^= _bin_to_long(u)
            return _long_to_bin(result, hex_format_string)

        T = [F(x) for x in range(1, l)]
        return b''.join(T) + F(l)[:r]


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