python类OrderBy()的实例源码

compiler.py 文件源码 项目:CodingDojo 作者: ComputerSocietyUNB 项目源码 文件源码 阅读 18 收藏 0 点赞 0 评论 0
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]
compiler.py 文件源码 项目:lifesoundtrack 作者: MTG 项目源码 文件源码 阅读 20 收藏 0 点赞 0 评论 0
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]
compiler.py 文件源码 项目:liberator 作者: libscie 项目源码 文件源码 阅读 25 收藏 0 点赞 0 评论 0
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]
compiler.py 文件源码 项目:djanoDoc 作者: JustinChavez 项目源码 文件源码 阅读 20 收藏 0 点赞 0 评论 0
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]
compiler.py 文件源码 项目:django-next-train 作者: bitpixdigital 项目源码 文件源码 阅读 22 收藏 0 点赞 0 评论 0
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]
compiler.py 文件源码 项目:LatinSounds_AppEnviaMail 作者: G3ek-aR 项目源码 文件源码 阅读 24 收藏 0 点赞 0 评论 0
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.is_relation and opts.ordering and getattr(field, 'attname', None) != name:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(getattr(self.query.alias_map[j], 'join_cols', None) for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]
compiler.py 文件源码 项目:django-wechat-api 作者: crazy-canux 项目源码 文件源码 阅读 21 收藏 0 点赞 0 评论 0
def find_ordering_name(self, name, opts, alias=None, default_order='ASC',
                           already_seen=None):
        """
        Returns the table alias (the name might be ambiguous, the alias will
        not be) and column name for ordering by the given 'name' parameter.
        The 'name' is of the form 'field1__field2__...__fieldN'.
        """
        name, order = get_order_dir(name, default_order)
        descending = True if order == 'DESC' else False
        pieces = name.split(LOOKUP_SEP)
        field, targets, alias, joins, path, opts = self._setup_joins(pieces, opts, alias)

        # If we get to this point and the field is a relation to another model,
        # append the default ordering for that model unless the attribute name
        # of the field is specified.
        if field.rel and path and opts.ordering and name != field.attname:
            # Firstly, avoid infinite loops.
            if not already_seen:
                already_seen = set()
            join_tuple = tuple(self.query.alias_map[j].table_name for j in joins)
            if join_tuple in already_seen:
                raise FieldError('Infinite loop caused by ordering.')
            already_seen.add(join_tuple)

            results = []
            for item in opts.ordering:
                results.extend(self.find_ordering_name(item, opts, alias,
                                                       order, already_seen))
            return results
        targets, alias, _ = self.query.trim_joins(targets, joins, path)
        return [(OrderBy(t.get_col(alias), descending=descending), False) for t in targets]


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