def format_week(self, char, num):
if char.islower(): # week of year
day_of_year = self.get_day_of_year()
week = self.get_week_number(day_of_year)
if week == 0:
date = self.value - timedelta(days=day_of_year)
week = self.get_week_number(self.get_day_of_year(date),
date.weekday())
return self.format(week, num)
else: # week of month
week = self.get_week_number(self.value.day)
if week == 0:
date = self.value - timedelta(days=self.value.day)
week = self.get_week_number(date.day, date.weekday())
pass
return '%d' % week
python类weekday()的实例源码
def format_week(self, char, num):
if char.islower(): # week of year
day_of_year = self.get_day_of_year()
week = self.get_week_number(day_of_year)
if week == 0:
date = self.value - timedelta(days=day_of_year)
week = self.get_week_number(self.get_day_of_year(date),
date.weekday())
return self.format(week, num)
else: # week of month
week = self.get_week_number(self.value.day)
if week == 0:
date = self.value - timedelta(days=self.value.day)
week = self.get_week_number(date.day, date.weekday())
pass
return '%d' % week
def format_week(self, char, num):
if char.islower(): # week of year
day_of_year = self.get_day_of_year()
week = self.get_week_number(day_of_year)
if week == 0:
date = self.value - timedelta(days=day_of_year)
week = self.get_week_number(self.get_day_of_year(date),
date.weekday())
return self.format(week, num)
else: # week of month
week = self.get_week_number(self.value.day)
if week == 0:
date = self.value - timedelta(days=self.value.day)
week = self.get_week_number(date.day, date.weekday())
pass
return '%d' % week
def format_weekday(self, char, num):
if num < 3:
if char.islower():
value = 7 - self.locale.first_week_day + self.value.weekday()
return self.format(value % 7 + 1, num)
num = 3
weekday = self.value.weekday()
width = {3: 'abbreviated', 4: 'wide', 5: 'narrow'}[num]
context = {3: 'format', 4: 'format', 5: 'stand-alone'}[num]
return get_day_names(width, context, self.locale)[weekday]
def get_week_number(self, day_of_period, day_of_week=None):
"""Return the number of the week of a day within a period. This may be
the week number in a year or the week number in a month.
Usually this will return a value equal to or greater than 1, but if the
first week of the period is so short that it actually counts as the last
week of the previous period, this function will return 0.
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('de_DE'))
>>> format.get_week_number(6)
1
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('en_US'))
>>> format.get_week_number(6)
2
:param day_of_period: the number of the day in the period (usually
either the day of month or the day of year)
:param day_of_week: the week day; if ommitted, the week day of the
current date is assumed
"""
if day_of_week is None:
day_of_week = self.value.weekday()
first_day = (day_of_week - self.locale.first_week_day -
day_of_period + 1) % 7
if first_day < 0:
first_day += 7
week_number = (day_of_period + first_day - 1) // 7
if 7 - first_day >= self.locale.min_week_days:
week_number += 1
return week_number
def format_week(self, char, num):
if char.islower(): # week of year
day_of_year = self.get_day_of_year()
week = self.get_week_number(day_of_year)
if week == 0:
date = self.value - timedelta(days=day_of_year)
week = self.get_week_number(self.get_day_of_year(date),
date.weekday())
return self.format(week, num)
else: # week of month
week = self.get_week_number(self.value.day)
if week == 0:
date = self.value - timedelta(days=self.value.day)
week = self.get_week_number(date.day, date.weekday())
return '%d' % week
def format_weekday(self, char, num):
if num < 3:
if char.islower():
value = 7 - self.locale.first_week_day + self.value.weekday()
return self.format(value % 7 + 1, num)
num = 3
weekday = self.value.weekday()
width = {3: 'abbreviated', 4: 'wide', 5: 'narrow'}[num]
context = {3: 'format', 4: 'format', 5: 'stand-alone'}[num]
return get_day_names(width, context, self.locale)[weekday]
def get_week_number(self, day_of_period, day_of_week=None):
"""Return the number of the week of a day within a period. This may be
the week number in a year or the week number in a month.
Usually this will return a value equal to or greater than 1, but if the
first week of the period is so short that it actually counts as the last
week of the previous period, this function will return 0.
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('de_DE'))
>>> format.get_week_number(6)
1
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('en_US'))
>>> format.get_week_number(6)
2
:param day_of_period: the number of the day in the period (usually
either the day of month or the day of year)
:param day_of_week: the week day; if ommitted, the week day of the
current date is assumed
"""
if day_of_week is None:
day_of_week = self.value.weekday()
first_day = (day_of_week - self.locale.first_week_day -
day_of_period + 1) % 7
if first_day < 0:
first_day += 7
week_number = (day_of_period + first_day - 1) // 7
if 7 - first_day >= self.locale.min_week_days:
week_number += 1
return week_number
def dateFormatter(self, date):
month = calendar.month_name[date.month]
weekday = calendar.day_name[date.weekday()]
day = date.day
year = date.year
results = str(weekday) + ", " + str(month) + " " + str(day) + ", " + str(year)
return results
def format_weekday(self, char, num):
if num < 3:
if char.islower():
value = 7 - self.locale.first_week_day + self.value.weekday()
return self.format(value % 7 + 1, num)
num = 3
weekday = self.value.weekday()
width = {3: 'abbreviated', 4: 'wide', 5: 'narrow'}[num]
context = {3: 'format', 4: 'format', 5: 'stand-alone'}[num]
return get_day_names(width, context, self.locale)[weekday]
def get_week_number(self, day_of_period, day_of_week=None):
"""Return the number of the week of a day within a period. This may be
the week number in a year or the week number in a month.
Usually this will return a value equal to or greater than 1, but if the
first week of the period is so short that it actually counts as the last
week of the previous period, this function will return 0.
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('de_DE'))
>>> format.get_week_number(6)
1
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('en_US'))
>>> format.get_week_number(6)
2
:param day_of_period: the number of the day in the period (usually
either the day of month or the day of year)
:param day_of_week: the week day; if ommitted, the week day of the
current date is assumed
"""
if day_of_week is None:
day_of_week = self.value.weekday()
first_day = (day_of_week - self.locale.first_week_day -
day_of_period + 1) % 7
if first_day < 0:
first_day += 7
week_number = (day_of_period + first_day - 1) // 7
if 7 - first_day >= self.locale.min_week_days:
week_number += 1
return week_number
def get_week_day(self,date):
day = date.weekday()
return self.__week_day_dict[day]
#TODO ????????
def getCommonDayMsg(self,date):
weekend = [5,6]
#?????
dayOfWeek = date.weekday()
#?????
if dayOfWeek in weekend:
content = "???",date.strftime('%b?%d?%?'),",",get_week_day(date),"?????????~"
return (time(9, 0, 0),content)
leftDay = 5 - dayOfWeek
content = "???",date.strftime('%b?%d?%?'),",",get_week_day(date),"??????",leftDay,"???????~"
return (time(7, 0, 0),content)
#TODO
def format_weekday(self, char, num):
if num < 3:
if char.islower():
value = 7 - self.locale.first_week_day + self.value.weekday()
return self.format(value % 7 + 1, num)
num = 3
weekday = self.value.weekday()
width = {3: 'abbreviated', 4: 'wide', 5: 'narrow'}[num]
context = {3: 'format', 4: 'format', 5: 'stand-alone'}[num]
return get_day_names(width, context, self.locale)[weekday]
def get_week_number(self, day_of_period, day_of_week=None):
"""Return the number of the week of a day within a period. This may be
the week number in a year or the week number in a month.
Usually this will return a value equal to or greater than 1, but if the
first week of the period is so short that it actually counts as the last
week of the previous period, this function will return 0.
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('de_DE'))
>>> format.get_week_number(6)
1
>>> format = DateTimeFormat(date(2006, 1, 8), Locale.parse('en_US'))
>>> format.get_week_number(6)
2
:param day_of_period: the number of the day in the period (usually
either the day of month or the day of year)
:param day_of_week: the week day; if ommitted, the week day of the
current date is assumed
"""
if day_of_week is None:
day_of_week = self.value.weekday()
first_day = (day_of_week - self.locale.first_week_day -
day_of_period + 1) % 7
if first_day < 0:
first_day += 7
week_number = (day_of_period + first_day - 1) // 7
if 7 - first_day >= self.locale.min_week_days:
week_number += 1
return week_number
