python类weekday()的实例源码

def convertTimestamp(self, ts):
        # 2050107034146B
        self.timetuple = [0,0,0,0,0,0,0,0,0]

        self.timetuple[0] = int(ts[0]) + int(ts[1]) * 10
        if self.timetuple[0] >= 80:
            # Convert to previous century, hopefully no one uses this after 2079 ;)
            self.timetuple[0] += 1900
        else:
            # Convert to current century
            self.timetuple[0] += 2000

        #~ print ts
        self.timetuple[1] = int(ts[2]) + int(ts[3]) * 10
        self.timetuple[2] = int(ts[4]) + int(ts[5]) * 10
        self.timetuple[3] = int(ts[6]) + int(ts[7]) * 10
        self.timetuple[4] = int(ts[8]) + int(ts[9]) * 10
        self.timetuple[5] = int(ts[10]) + int(ts[11]) * 10
        self.timetuple[6] = calendar.weekday(self.timetuple[0], self.timetuple[1], self.timetuple[2])

        return time.asctime(self.timetuple)

def strptime(date):
    """Convert the date string into a 9 tuple"""
    df = [0,0,0,0,0,0,0,0,0]
    sp  = date.split(' ')
    spt = sp[3].split(':')

    df[0] = int(sp[4])      # Year
    if abbrevMonthNames.has_key(sp[1]):
        df[1] = int(abbrevMonthNames[sp[1]])
    else:
        df[1] = 1           # Month
    df[2] = int(sp[2])      # Day
    df[3] = int(spt[0])     # Hour
    df[4] = int(spt[1])     # Minute
    df[5] = int(spt[2])     # Second
    df[6] = calendar.weekday(df[0], df[1], df[2])

    return df

def test_W_wildcard(self):
        years = [2016, 2017]  # leap and normal year

        for year in years:
            for month in range(1, 13):
                _, days = calendar.monthrange(year, month)

                for day in range(1, days):
                    weekday = calendar.weekday(year, month, day)
                    result = day
                    if weekday == 5:
                        result = day - 1 if day > 1 else day + 2
                    elif weekday == 6:
                        result = day + 1 if day < days else  day - 2

                    self.assertEquals(MonthdaySetBuilder(year, month).build(str(day) + "W"), {result})

def is_valid_date(given_date):
    """
    Given a date string this function checks if the date is in the future
    """

    given_date = given_date.split("/")
    current_date = get_current_date().split("/")

    given_day = int(given_date[1])
    given_month = int(given_date[0])
    given_year = int(given_date[2])

    current_day = int(current_date[1])
    current_month = int(current_date[0])
    current_year = int(current_date[2])

    try:
        calendar.weekday(given_year, given_month, given_day)
    except ValueError:
        return False

    return (
        (given_year == current_year and given_month == current_month and given_day > current_day) or
        (given_year == current_year and given_month > current_month) or
        (given_year > current_year))

def dayofweek(day, month, year, format=True):
    import calendar
    if format == False:
        return calendar.weekday(year, month, day) + 1
    else:
        if calendar.weekday(year, month, day) == 0:
            return 'Monday'
        elif calendar.weekday(year, month, day) == 1:
            return 'Tuesday'
        elif calendar.weekday(year, month, day) == 2:
            return 'Wednesday'
        elif calendar.weekday(year, month, day) == 3:
            return 'Thursday'
        elif calendar.weekday(year, month, day) == 4:
            return 'Friday'
        elif calendar.weekday(year, month, day) == 5:
            return 'Saturday'
        elif calendar.weekday(year, month, day) == 6:
            return 'Sunday'

# Check If A Year Is A Leap Year

def calcDate():
    now = date.today()
    dateList=[]

    one_day = timedelta(days=1)
    calcDate=now
    charweek=("?","?","?","?","?","?","?")

    for i in range(7):
        calcDate=calcDate+one_day
        year=calcDate.year
        month=calcDate.month
        day=calcDate.day
        week=weekday(year,month,day)
        strdate=str(month)+"/"+str(day)+"("+charweek[week]+") 19:00?\n"
        dateList.append(strdate)

    return dateList

def __init__(self, *args, **keys):
        self._spec = {}

        max_priority = min(x.time_tuple_index for x in self._units.values())

        for key, arg in dict(*args, **keys).iteritems():
            if key not in self._units:
                raise TypeError("unexpected unit {0!r}".format(key))

            unit = self._units[key]
            max_priority = max(max_priority, unit.time_tuple_index)
            rangeobj = self._coerce(arg)
            self._spec[key] = unit.resolve(rangeobj)

        for key, unit in self._units.iteritems():
            if key in self._spec:
                continue

            if max_priority >= unit.time_tuple_index:
                self._spec[key] = unit.resolve(any())
            else:
                self._spec[key] = unit.resolve(value(unit.min))

        # Special case: If both day or weekday is limited, then use OR instead of AND.
        if self._is_any("day"):
            self._spec["day"] = self._units["day"].resolve(empty())
        elif self._is_any("weekday"):
            self._spec["weekday"] = self._units["weekday"].resolve(empty())
        self._spec["day"] = _ResolvedOr(self._spec.pop("day"), self._spec.pop("weekday"))

def get_weekday_format(year, month, day, include_weekend=True):
    """return numeric day in string if weekday else day with WEEKEND_SYMBOL"""
    weekend = [calendar.SATURDAY, calendar.SUNDAY]
    d = calendar.weekday(year, month, day)
    # highlight_wkend = False
    # global WEEKEND_SYMBOL

    # WEEKEND_SYMBOL = ' '
    if d in weekend:
        if include_weekend:
            return "{ws}{day}  ".format(ws=WEEKEND_SYMBOL, day=day)
        else:
            return ""

    return " {day}  ".format(day=day)

def begin_end_week_day(current_day, delay=0):
    begin = (datetime.now() - timedelta(days=current_day.weekday())) + timedelta(days=7 * delay)
    end = begin + timedelta(days=4)
    return begin, end

def unlucky_days(year):
    return sum(weekday(year, month, 13) == 4 for month in range(1, 13))