python类Or()的实例源码

markers.py 文件源码 项目:flasky 作者: RoseOu 项目源码 文件源码 阅读 20 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:flickr_downloader 作者: Denisolt 项目源码 文件源码 阅读 20 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:threatdetectionservice 作者: flyballlabs 项目源码 文件源码 阅读 18 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:oa_qian 作者: sunqb 项目源码 文件源码 阅读 70 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:RealtimePythonChat 作者: quangtqag 项目源码 文件源码 阅读 21 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:Indushell 作者: SecarmaLabs 项目源码 文件源码 阅读 18 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:SHAREOpenRefineWkshop 作者: cmh2166 项目源码 文件源码 阅读 21 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:Liljimbo-Chatbot 作者: chrisjim316 项目源码 文件源码 阅读 18 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:leetcode 作者: thomasyimgit 项目源码 文件源码 阅读 28 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:flask_system 作者: prashasy 项目源码 文件源码 阅读 24 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:news-for-good 作者: thecodinghub 项目源码 文件源码 阅读 21 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:CaScale 作者: Thatsillogical 项目源码 文件源码 阅读 19 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:chihu 作者: yelongyu 项目源码 文件源码 阅读 17 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:ShelbySearch 作者: Agentscreech 项目源码 文件源码 阅读 23 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:where2live 作者: fbessez 项目源码 文件源码 阅读 19 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:pyetje 作者: rorlika 项目源码 文件源码 阅读 21 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:respeaker_virtualenv 作者: respeaker 项目源码 文件源码 阅读 20 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:Tencent_Cartoon_Download 作者: Fretice 项目源码 文件源码 阅读 20 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:Problematica-public 作者: TechMaz 项目源码 文件源码 阅读 19 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result
markers.py 文件源码 项目:bawk 作者: jttwnsnd 项目源码 文件源码 阅读 29 收藏 0 点赞 0 评论 0
def do_boolop(self, node):
        result = self.evaluate(node.values[0])
        is_or = node.op.__class__ is ast.Or
        is_and = node.op.__class__ is ast.And
        assert is_or or is_and
        if (is_and and result) or (is_or and not result):
            for n in node.values[1:]:
                result = self.evaluate(n)
                if (is_or and result) or (is_and and not result):
                    break
        return result


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