def compile_path(skip_curdir=1, maxlevels=0, force=0, quiet=0):
"""Byte-compile all module on sys.path.
Arguments (all optional):
skip_curdir: if true, skip current directory (default true)
maxlevels: max recursion level (default 0)
force: as for compile_dir() (default 0)
quiet: as for compile_dir() (default 0)
"""
success = 1
for dir in sys.path:
if (not dir or dir == os.curdir) and skip_curdir:
print 'Skipping current directory'
else:
success = success and compile_dir(dir, maxlevels, None,
force, quiet=quiet)
return success
python类compile()的实例源码
def multireplace(string, replacements):
"""
Given a string and a replacement map, it returns the replaced string.
:param str string: string to execute replacements on
:param dict replacements: replacement dictionary {value to find: value to replace}
:rtype: str
"""
# Place longer ones first to keep shorter substrings from matching where the longer ones should take place
# For instance given the replacements {'ab': 'AB', 'abc': 'ABC'} against the string 'hey abc', it should produce
# 'hey ABC' and not 'hey ABc'
substrs = sorted(replacements, key=len, reverse=True)
# Create a big OR regex that matches any of the substrings to replace
regexp = re.compile('|'.join(map(re.escape, substrs)))
# For each match, look up the new string in the replacements
return regexp.sub(lambda match: replacements[match.group(0)], string)
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
codestring = open(pathname, 'rU').read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
codestring = open(pathname, 'rU').read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def main(args=None):
"""Compile several source files.
The files named in 'args' (or on the command line, if 'args' is
not specified) are compiled and the resulting bytecode is cached
in the normal manner. This function does not search a directory
structure to locate source files; it only compiles files named
explicitly. If '-' is the only parameter in args, the list of
files is taken from standard input.
"""
if args is None:
args = sys.argv[1:]
rv = 0
if args == ['-']:
while True:
filename = sys.stdin.readline()
if not filename:
break
filename = filename.rstrip('\n')
try:
compile(filename, doraise=True)
except PyCompileError as error:
rv = 1
sys.stderr.write("%s\n" % error.msg)
except IOError as error:
rv = 1
sys.stderr.write("%s\n" % error)
else:
for filename in args:
try:
compile(filename, doraise=True)
except PyCompileError as error:
# return value to indicate at least one failure
rv = 1
sys.stderr.write(error.msg)
return rv
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
codestring = open(pathname, 'rU').read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def main(args=None):
"""Compile several source files.
The files named in 'args' (or on the command line, if 'args' is
not specified) are compiled and the resulting bytecode is cached
in the normal manner. This function does not search a directory
structure to locate source files; it only compiles files named
explicitly. If '-' is the only parameter in args, the list of
files is taken from standard input.
"""
if args is None:
args = sys.argv[1:]
rv = 0
if args == ['-']:
while True:
filename = sys.stdin.readline()
if not filename:
break
filename = filename.rstrip('\n')
try:
compile(filename, doraise=True)
except PyCompileError as error:
rv = 1
sys.stderr.write("%s\n" % error.msg)
except IOError as error:
rv = 1
sys.stderr.write("%s\n" % error)
else:
for filename in args:
try:
compile(filename, doraise=True)
except PyCompileError as error:
# return value to indicate at least one failure
rv = 1
sys.stderr.write("%s\n" % error.msg)
return rv
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
codestring = open(pathname, 'rU').read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def main(args=None):
"""Compile several source files.
The files named in 'args' (or on the command line, if 'args' is
not specified) are compiled and the resulting bytecode is cached
in the normal manner. This function does not search a directory
structure to locate source files; it only compiles files named
explicitly. If '-' is the only parameter in args, the list of
files is taken from standard input.
"""
if args is None:
args = sys.argv[1:]
rv = 0
if args == ['-']:
while True:
filename = sys.stdin.readline()
if not filename:
break
filename = filename.rstrip('\n')
try:
compile(filename, doraise=True)
except PyCompileError as error:
rv = 1
sys.stderr.write("%s\n" % error.msg)
except IOError as error:
rv = 1
sys.stderr.write("%s\n" % error)
else:
for filename in args:
try:
compile(filename, doraise=True)
except PyCompileError as error:
# return value to indicate at least one failure
rv = 1
sys.stderr.write("%s\n" % error.msg)
return rv
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
codestring = open(pathname, 'rU').read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def main(args=None):
"""Compile several source files.
The files named in 'args' (or on the command line, if 'args' is
not specified) are compiled and the resulting bytecode is cached
in the normal manner. This function does not search a directory
structure to locate source files; it only compiles files named
explicitly. If '-' is the only parameter in args, the list of
files is taken from standard input.
"""
if args is None:
args = sys.argv[1:]
rv = 0
if args == ['-']:
while True:
filename = sys.stdin.readline()
if not filename:
break
filename = filename.rstrip('\n')
try:
compile(filename, doraise=True)
except PyCompileError as error:
rv = 1
sys.stderr.write("%s\n" % error.msg)
except IOError as error:
rv = 1
sys.stderr.write("%s\n" % error)
else:
for filename in args:
try:
compile(filename, doraise=True)
except PyCompileError as error:
# return value to indicate at least one failure
rv = 1
sys.stderr.write(error.msg)
return rv
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
with open(pathname, 'rU') as fp:
codestring = fp.read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def main(args=None):
"""Compile several source files.
The files named in 'args' (or on the command line, if 'args' is
not specified) are compiled and the resulting bytecode is cached
in the normal manner. This function does not search a directory
structure to locate source files; it only compiles files named
explicitly. If '-' is the only parameter in args, the list of
files is taken from standard input.
"""
if args is None:
args = sys.argv[1:]
rv = 0
if args == ['-']:
while True:
filename = sys.stdin.readline()
if not filename:
break
filename = filename.rstrip('\n')
try:
compile(filename, doraise=True)
except PyCompileError as error:
rv = 1
sys.stderr.write("%s\n" % error.msg)
except IOError as error:
rv = 1
sys.stderr.write("%s\n" % error)
else:
for filename in args:
try:
compile(filename, doraise=True)
except PyCompileError as error:
# return value to indicate at least one failure
rv = 1
sys.stderr.write(error.msg)
return rv
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
codestring = open(pathname, 'rU').read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def main(args=None):
"""Compile several source files.
The files named in 'args' (or on the command line, if 'args' is
not specified) are compiled and the resulting bytecode is cached
in the normal manner. This function does not search a directory
structure to locate source files; it only compiles files named
explicitly. If '-' is the only parameter in args, the list of
files is taken from standard input.
"""
if args is None:
args = sys.argv[1:]
rv = 0
if args == ['-']:
while True:
filename = sys.stdin.readline()
if not filename:
break
filename = filename.rstrip('\n')
try:
compile(filename, doraise=True)
except PyCompileError as error:
rv = 1
sys.stderr.write("%s\n" % error.msg)
except IOError as error:
rv = 1
sys.stderr.write("%s\n" % error)
else:
for filename in args:
try:
compile(filename, doraise=True)
except PyCompileError as error:
# return value to indicate at least one failure
rv = 1
sys.stderr.write(error.msg)
return rv
def _compile(pathname, timestamp):
"""Compile (and cache) a Python source file.
The file specified by <pathname> is compiled to a code object and
returned.
Presuming the appropriate privileges exist, the bytecodes will be
saved back to the filesystem for future imports. The source file's
modification timestamp must be provided as a Long value.
"""
codestring = open(pathname, 'rU').read()
if codestring and codestring[-1] != '\n':
codestring = codestring + '\n'
code = __builtin__.compile(codestring, pathname, 'exec')
# try to cache the compiled code
try:
f = open(pathname + _suffix_char, 'wb')
except IOError:
pass
else:
f.write('\0\0\0\0')
f.write(struct.pack('<I', timestamp))
marshal.dump(code, f)
f.flush()
f.seek(0, 0)
f.write(imp.get_magic())
f.close()
return code
def compile_dir(dir, maxlevels=10, ddir=None,
force=0, rx=None, quiet=0):
"""Byte-compile all modules in the given directory tree.
Arguments (only dir is required):
dir: the directory to byte-compile
maxlevels: maximum recursion level (default 10)
ddir: the directory that will be prepended to the path to the
file as it is compiled into each byte-code file.
force: if 1, force compilation, even if timestamps are up-to-date
quiet: if 1, be quiet during compilation
"""
if not quiet:
print 'Listing', dir, '...'
try:
names = os.listdir(dir)
except os.error:
print "Can't list", dir
names = []
names.sort()
success = 1
for name in names:
fullname = os.path.join(dir, name).replace(os.sep, '/')
if ddir is not None:
dfile = os.path.join(ddir, name).replace(os.sep, '/')
else:
dfile = None
if not os.path.isdir(fullname):
if not compile_file(fullname, ddir, force, rx, quiet):
success = 0
elif maxlevels > 0 and \
name != os.curdir and name != os.pardir and \
os.path.isdir(fullname) and \
not os.path.islink(fullname):
if not compile_dir(fullname, maxlevels - 1, dfile, force, rx,
quiet):
success = 0
return success
def create_pyc(codestring, cfile, timestamp=None):
if timestamp is None:
timestamp = time()
codeobject = builtins.compile(codestring, '<recompile>', 'exec')
cfile.write(MAGIC)
cfile.write(struct.pack('i', timestamp))
marshal.dump(codeobject, cfile)
cfile.flush()
def compile(file, cfile=None, dfile=None, doraise=False):
"""Byte-compile one Python source file to Python bytecode.
Arguments:
file: source filename
cfile: target filename; defaults to source with 'c' or 'o' appended
('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
dfile: purported filename; defaults to source (this is the filename
that will show up in error messages)
doraise: flag indicating whether or not an exception should be
raised when a compile error is found. If an exception
occurs and this flag is set to False, a string
indicating the nature of the exception will be printed,
and the function will return to the caller. If an
exception occurs and this flag is set to True, a
PyCompileError exception will be raised.
Note that it isn't necessary to byte-compile Python modules for
execution efficiency -- Python itself byte-compiles a module when
it is loaded, and if it can, writes out the bytecode to the
corresponding .pyc (or .pyo) file.
However, if a Python installation is shared between users, it is a
good idea to byte-compile all modules upon installation, since
other users may not be able to write in the source directories,
and thus they won't be able to write the .pyc/.pyo file, and then
they would be byte-compiling every module each time it is loaded.
This can slow down program start-up considerably.
See compileall.py for a script/module that uses this module to
byte-compile all installed files (or all files in selected
directories).
"""
with open(file, 'U') as f:
try:
timestamp = long(os.fstat(f.fileno()).st_mtime)
except AttributeError:
timestamp = long(os.stat(file).st_mtime)
codestring = f.read()
try:
codeobject = __builtin__.compile(codestring, dfile or file,'exec')
except Exception,err:
py_exc = PyCompileError(err.__class__, err, dfile or file)
if doraise:
raise py_exc
else:
sys.stderr.write(py_exc.msg + '\n')
return
if cfile is None:
cfile = file + (__debug__ and 'c' or 'o')
with open(cfile, 'wb') as fc:
fc.write('\0\0\0\0')
wr_long(fc, timestamp)
marshal.dump(codeobject, fc)
fc.flush()
fc.seek(0, 0)
fc.write(MAGIC)
def compile(file, cfile=None, dfile=None, doraise=False):
"""Byte-compile one Python source file to Python bytecode.
Arguments:
file: source filename
cfile: target filename; defaults to source with 'c' or 'o' appended
('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
dfile: purported filename; defaults to source (this is the filename
that will show up in error messages)
doraise: flag indicating whether or not an exception should be
raised when a compile error is found. If an exception
occurs and this flag is set to False, a string
indicating the nature of the exception will be printed,
and the function will return to the caller. If an
exception occurs and this flag is set to True, a
PyCompileError exception will be raised.
Note that it isn't necessary to byte-compile Python modules for
execution efficiency -- Python itself byte-compiles a module when
it is loaded, and if it can, writes out the bytecode to the
corresponding .pyc (or .pyo) file.
However, if a Python installation is shared between users, it is a
good idea to byte-compile all modules upon installation, since
other users may not be able to write in the source directories,
and thus they won't be able to write the .pyc/.pyo file, and then
they would be byte-compiling every module each time it is loaded.
This can slow down program start-up considerably.
See compileall.py for a script/module that uses this module to
byte-compile all installed files (or all files in selected
directories).
"""
with open(file, 'U') as f:
try:
timestamp = long(os.fstat(f.fileno()).st_mtime)
except AttributeError:
timestamp = long(os.stat(file).st_mtime)
codestring = f.read()
try:
codeobject = __builtin__.compile(codestring, dfile or file,'exec')
except Exception,err:
py_exc = PyCompileError(err.__class__, err, dfile or file)
if doraise:
raise py_exc
else:
sys.stderr.write(py_exc.msg + '\n')
return
if cfile is None:
cfile = file + (__debug__ and 'c' or 'o')
with open(cfile, 'wb') as fc:
fc.write('\0\0\0\0')
wr_long(fc, timestamp)
marshal.dump(codeobject, fc)
fc.flush()
fc.seek(0, 0)
fc.write(MAGIC)
def compile(file, cfile=None, dfile=None, doraise=False):
"""Byte-compile one Python source file to Python bytecode.
Arguments:
file: source filename
cfile: target filename; defaults to source with 'c' or 'o' appended
('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
dfile: purported filename; defaults to source (this is the filename
that will show up in error messages)
doraise: flag indicating whether or not an exception should be
raised when a compile error is found. If an exception
occurs and this flag is set to False, a string
indicating the nature of the exception will be printed,
and the function will return to the caller. If an
exception occurs and this flag is set to True, a
PyCompileError exception will be raised.
Note that it isn't necessary to byte-compile Python modules for
execution efficiency -- Python itself byte-compiles a module when
it is loaded, and if it can, writes out the bytecode to the
corresponding .pyc (or .pyo) file.
However, if a Python installation is shared between users, it is a
good idea to byte-compile all modules upon installation, since
other users may not be able to write in the source directories,
and thus they won't be able to write the .pyc/.pyo file, and then
they would be byte-compiling every module each time it is loaded.
This can slow down program start-up considerably.
See compileall.py for a script/module that uses this module to
byte-compile all installed files (or all files in selected
directories).
"""
with open(file, 'U') as f:
try:
timestamp = long(os.fstat(f.fileno()).st_mtime)
except AttributeError:
timestamp = long(os.stat(file).st_mtime)
codestring = f.read()
try:
codeobject = __builtin__.compile(codestring, dfile or file,'exec')
except Exception,err:
py_exc = PyCompileError(err.__class__, err, dfile or file)
if doraise:
raise py_exc
else:
sys.stderr.write(py_exc.msg + '\n')
return
if cfile is None:
cfile = file + (__debug__ and 'c' or 'o')
with open(cfile, 'wb') as fc:
fc.write('\0\0\0\0')
wr_long(fc, timestamp)
marshal.dump(codeobject, fc)
fc.flush()
fc.seek(0, 0)
fc.write(MAGIC)
def compile(file, cfile=None, dfile=None, doraise=False):
"""Byte-compile one Python source file to Python bytecode.
Arguments:
file: source filename
cfile: target filename; defaults to source with 'c' or 'o' appended
('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
dfile: purported filename; defaults to source (this is the filename
that will show up in error messages)
doraise: flag indicating whether or not an exception should be
raised when a compile error is found. If an exception
occurs and this flag is set to False, a string
indicating the nature of the exception will be printed,
and the function will return to the caller. If an
exception occurs and this flag is set to True, a
PyCompileError exception will be raised.
Note that it isn't necessary to byte-compile Python modules for
execution efficiency -- Python itself byte-compiles a module when
it is loaded, and if it can, writes out the bytecode to the
corresponding .pyc (or .pyo) file.
However, if a Python installation is shared between users, it is a
good idea to byte-compile all modules upon installation, since
other users may not be able to write in the source directories,
and thus they won't be able to write the .pyc/.pyo file, and then
they would be byte-compiling every module each time it is loaded.
This can slow down program start-up considerably.
See compileall.py for a script/module that uses this module to
byte-compile all installed files (or all files in selected
directories).
"""
with open(file, 'U') as f:
try:
timestamp = long(os.fstat(f.fileno()).st_mtime)
except AttributeError:
timestamp = long(os.stat(file).st_mtime)
codestring = f.read()
try:
codeobject = __builtin__.compile(codestring, dfile or file,'exec')
except Exception,err:
py_exc = PyCompileError(err.__class__, err, dfile or file)
if doraise:
raise py_exc
else:
sys.stderr.write(py_exc.msg + '\n')
return
if cfile is None:
cfile = file + (__debug__ and 'c' or 'o')
with open(cfile, 'wb') as fc:
fc.write('\0\0\0\0')
wr_long(fc, timestamp)
marshal.dump(codeobject, fc)
fc.flush()
fc.seek(0, 0)
fc.write(MAGIC)
def compile(file, cfile=None, dfile=None, doraise=False):
"""Byte-compile one Python source file to Python bytecode.
Arguments:
file: source filename
cfile: target filename; defaults to source with 'c' or 'o' appended
('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
dfile: purported filename; defaults to source (this is the filename
that will show up in error messages)
doraise: flag indicating whether or not an exception should be
raised when a compile error is found. If an exception
occurs and this flag is set to False, a string
indicating the nature of the exception will be printed,
and the function will return to the caller. If an
exception occurs and this flag is set to True, a
PyCompileError exception will be raised.
Note that it isn't necessary to byte-compile Python modules for
execution efficiency -- Python itself byte-compiles a module when
it is loaded, and if it can, writes out the bytecode to the
corresponding .pyc (or .pyo) file.
However, if a Python installation is shared between users, it is a
good idea to byte-compile all modules upon installation, since
other users may not be able to write in the source directories,
and thus they won't be able to write the .pyc/.pyo file, and then
they would be byte-compiling every module each time it is loaded.
This can slow down program start-up considerably.
See compileall.py for a script/module that uses this module to
byte-compile all installed files (or all files in selected
directories).
"""
with open(file, 'U') as f:
try:
timestamp = long(os.fstat(f.fileno()).st_mtime)
except AttributeError:
timestamp = long(os.stat(file).st_mtime)
codestring = f.read()
try:
codeobject = __builtin__.compile(codestring, dfile or file,'exec')
except Exception,err:
py_exc = PyCompileError(err.__class__, err, dfile or file)
if doraise:
raise py_exc
else:
sys.stderr.write(py_exc.msg + '\n')
return
if cfile is None:
cfile = file + (__debug__ and 'c' or 'o')
with open(cfile, 'wb') as fc:
fc.write('\0\0\0\0')
wr_long(fc, timestamp)
marshal.dump(codeobject, fc)
fc.flush()
fc.seek(0, 0)
fc.write(MAGIC)
def compile(file, cfile=None, dfile=None, doraise=False):
"""Byte-compile one Python source file to Python bytecode.
Arguments:
file: source filename
cfile: target filename; defaults to source with 'c' or 'o' appended
('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
dfile: purported filename; defaults to source (this is the filename
that will show up in error messages)
doraise: flag indicating whether or not an exception should be
raised when a compile error is found. If an exception
occurs and this flag is set to False, a string
indicating the nature of the exception will be printed,
and the function will return to the caller. If an
exception occurs and this flag is set to True, a
PyCompileError exception will be raised.
Note that it isn't necessary to byte-compile Python modules for
execution efficiency -- Python itself byte-compiles a module when
it is loaded, and if it can, writes out the bytecode to the
corresponding .pyc (or .pyo) file.
However, if a Python installation is shared between users, it is a
good idea to byte-compile all modules upon installation, since
other users may not be able to write in the source directories,
and thus they won't be able to write the .pyc/.pyo file, and then
they would be byte-compiling every module each time it is loaded.
This can slow down program start-up considerably.
See compileall.py for a script/module that uses this module to
byte-compile all installed files (or all files in selected
directories).
"""
with open(file, 'U') as f:
try:
timestamp = long(os.fstat(f.fileno()).st_mtime)
except AttributeError:
timestamp = long(os.stat(file).st_mtime)
codestring = f.read()
try:
codeobject = __builtin__.compile(codestring, dfile or file,'exec')
except Exception,err:
py_exc = PyCompileError(err.__class__, err, dfile or file)
if doraise:
raise py_exc
else:
sys.stderr.write(py_exc.msg + '\n')
return
if cfile is None:
cfile = file + (__debug__ and 'c' or 'o')
with open(cfile, 'wb') as fc:
fc.write('\0\0\0\0')
wr_long(fc, timestamp)
marshal.dump(codeobject, fc)
fc.flush()
fc.seek(0, 0)
fc.write(MAGIC)
def compile_file(fullname, ddir=None, force=0, rx=None, quiet=0):
"""Byte-compile one file.
Arguments (only fullname is required):
fullname: the file to byte-compile
ddir: if given, the directory name compiled in to the
byte-code file.
force: if 1, force compilation, even if timestamps are up-to-date
quiet: if 1, be quiet during compilation
"""
success = 1
name = os.path.basename(fullname)
if ddir is not None:
dfile = os.path.join(ddir, name).replace(os.sep, '/')
else:
dfile = None
if rx is not None:
mo = rx.search(fullname)
if mo:
return success
if os.path.isfile(fullname):
head, tail = name[:-3], name[-3:]
if tail == '.py':
timeStr = subprocess.check_output(
['git', '--no-pager', 'log', '-n', '1', '--format="%ct"', '--', fullname])[1:-2]
if not force:
try:
if not timeStr:
mtime = int(os.stat(fullname).st_mtime)
else:
mtime = int(timeStr)
expect = struct.pack('<4sl', imp.get_magic(), mtime)
cfile = fullname + (__debug__ and 'c' or 'o')
with open(cfile, 'rb') as chandle:
actual = chandle.read(8)
if expect == actual:
return success
except IOError:
pass
if not quiet:
print 'Compiling', fullname, '...'
try:
ok = do_compile(fullname, None, dfile, True, timeStr)
except py_compile.PyCompileError, err:
if quiet:
print 'Compiling', fullname, '...'
print err.msg
success = 0
except IOError, e:
print "Sorry", e
success = 0
else:
if ok == 0:
success = 0
return success
