/**
* BiMap存储数据时出现冲突
* 存储时,如果key相同,则会覆盖,则逆转后不会有问题
* 存储时,如果key不同,value有相同,则逆转时会抛出异常IllegalArgumentException
*/
@Test
public void testConflictInsertKV() {
// 存储相同key数据,此时会覆盖k1=v1
BiMap<String, String> biMap1 = HashBiMap.create();
biMap1.put("k1", "v1");
biMap1.put("k1", "v2");
System.out.println("biMap1: " + biMap1);
// 获取的只有 v2=k1
BiMap<String, String> inverseBiMap1 = biMap1.inverse();
System.out.println("inverseBiMap1: " + inverseBiMap1);
System.out.println("--------------------------------------");
// 存储相同的value数据
BiMap<String, String> biMap2 = HashBiMap.create();
biMap2.put("k1", "v1");
// 此时抛出异常 java.lang.IllegalArgumentException: value already present: v1
biMap2.put("k2", "v1");
System.out.println("biMap2: " + biMap2);
BiMap<String, String> inverseBiMap2 = biMap2.inverse();
System.out.println("inverseBiMap2: " + inverseBiMap2);
}
HashBiMapDemo.java 文件源码
java
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