employeeController.py 文件源码

python
阅读 20 收藏 0 点赞 0 评论 0

项目:metronus 作者: Metronus 项目源码 文件源码
def list_employees_search(request,name):
    """
    parameters/returns:
    employees: lista de objetos employee a los que tiene acceso el administrador (los que están en su empresa)

    template: employee_list.html
    """

    # Check that the current user has permissions
    lista = get_list_for_role(request)
    if name != "all_true":
        #little opt just if not empty
        lista=lista.annotate(
                search_name=Concat('user__first_name', V(' '), 'user__last_name')
                ).filter(search_name__icontains=name)
    employees = lista.filter(user__is_active=True)

    return render(request, "employee/employee_search.html",
        {"employees": employees})
评论列表
文章目录


问题


面经


文章

微信
公众号

扫码关注公众号