test_trix_serialize.py 文件源码

def testSerialize(self):

        s1 = URIRef('store:1')
        r1 = URIRef('resource:1')
        r2 = URIRef('resource:2')

        label = URIRef('predicate:label')

        g1 = Graph(identifier=s1)
        g1.add((r1, label, Literal("label 1", lang="en")))
        g1.add((r1, label, Literal("label 2")))

        s2 = URIRef('store:2')
        g2 = Graph(identifier=s2)
        g2.add((r2, label, Literal("label 3")))

        g = ConjunctiveGraph()
        for s, p, o in g1.triples((None, None, None)):
            g.addN([(s, p, o, g1)])
        for s, p, o in g2.triples((None, None, None)):
            g.addN([(s, p, o, g2)])
        r3 = URIRef('resource:3')
        g.add((r3, label, Literal(4)))

        r = g.serialize(format='trix')
        g3 = ConjunctiveGraph()

        g3.parse(BytesIO(r), format='trix')

        for q in g3.quads((None, None, None)):
            # TODO: Fix once getGraph/getContext is in conjunctive graph
            if isinstance(q[3].identifier, URIRef):
                tg = Graph(store=g.store, identifier=q[3].identifier)
            else:
                # BNode, this is a bit ugly
                # we cannot match the bnode to the right graph automagically
                # here I know there is only one anonymous graph,
                # and that is the default one, but this is not always the case
                tg = g.default_context
            self.assert_(q[0:3] in tg)