def get_folder_menu(self, obj, folder, path):
if not obj or not (isinstance(obj,gtk.Menu) or isinstance(obj,gtk.MenuItem)):
return None
for item in obj.get_children():
if path == folder+'/'+item.get_label():
return item.get_submenu()
i = self.get_folder_menu(item.get_submenu(), folder+'/'+item.get_label(), path)
if i:
return i
gnome_connection_manager.py 文件源码
python
阅读 19
收藏 0
点赞 0
评论 0
评论列表
文章目录