test_dle.py 文件源码

def _new_operator3(shape, time_order, **kwargs):
    grid = Grid(shape=shape)
    spacing = 0.1
    a = 0.5
    c = 0.5
    dx2, dy2 = spacing**2, spacing**2
    dt = dx2 * dy2 / (2 * a * (dx2 + dy2))

    # Allocate the grid and set initial condition
    # Note: This should be made simpler through the use of defaults
    u = TimeFunction(name='u', grid=grid, time_order=1, space_order=2)
    u.data[0, :] = np.arange(reduce(mul, shape), dtype=np.int32).reshape(shape)

    # Derive the stencil according to devito conventions
    eqn = Eq(u.dt, a * (u.dx2 + u.dy2) - c * (u.dxl + u.dyl))
    stencil = solve(eqn, u.forward, rational=False)[0]
    op = Operator(Eq(u.forward, stencil), **kwargs)

    # Execute the generated Devito stencil operator
    op.apply(u=u, t=10, dt=dt)
    return u.data[1, :], op