def _optimal_step_size(last_step,
error_ratio,
safety=0.9,
ifactor=10.0,
dfactor=0.2,
order=5,
name=None):
"""Calculate the optimal size for the next Runge-Kutta step."""
with ops.name_scope(
name, 'optimal_step_size', [last_step, error_ratio]) as scope:
error_ratio = math_ops.cast(error_ratio, last_step.dtype)
exponent = math_ops.cast(1 / order, last_step.dtype)
# this looks more complex than necessary, but importantly it keeps
# error_ratio in the numerator so we can't divide by zero:
factor = math_ops.maximum(
1 / ifactor,
math_ops.minimum(error_ratio ** exponent / safety, 1 / dfactor))
return math_ops.div(last_step, factor, name=scope)
odes.py 文件源码
python
阅读 18
收藏 0
点赞 0
评论 0
评论列表
文章目录