stats.py 文件源码

def norm_std_from_iqr(mu, iqr):
    """Computes the standard deviation of a normal distribution with mean mu and IQR irq."""
    # Assuming normal distribution (so symmetric), Q1 = m - (iqr / 2)
    Q1 = mu - (iqr / 2.0)
    # Assuming a normal distribution with mean m, std s, and first quartile Q1,
    # we have (Q1 - m)/s = ppf(0.25)
    return (Q1 - mu) / norm.ppf(0.25)