pyldfire.py 文件源码

def submit_remote_file(self, url):
        """Submits a file from a remote URL for analysis

        Args:
            url (str): The URL where the file is located

        Returns:
            dict: Analysis results

        Raises:
             WildFireException: If an API error occurs

        Notes:
            This is for submitting files located at remote URLs, not web pages.

        See Also:
            submit_urls(self, urls)
        """

        request_url = "{0}{1}".format(self.api_root, "/submit/url")
        data = dict(apikey=self.api_key, url=url)
        response = self.session.post(request_url, data=data)

        return xmltodict.parse(response.text)['wildfire']['upload-file-info']