files.py 文件源码

def serve_zip_file(submissions, zipname="zipfile"):
    """
    Takes a list of submissions and generates a streaming response from them
    """
    resp = StreamingHttpResponse(submissions_zip_generator(submissions), content_type="application/zip")
    resp["Content-Disposition"] = "attachment; filename={zipname}.zip".format(zipname=zipname)
    return resp