inline_list.py 文件源码

def run(self, lines):
        HEADER_REGEX = re.compile('\{\{inline\(list\)::\n(.*?)\n\}\}', re.DOTALL)  # maybe too much sensitive

        def replace(m):
            text = m.groups()[0]
            md = Markdown()
            table = md.convert(text).replace("\n", "")
            return table

        new_lines = HEADER_REGEX.sub(replace, "\n".join(lines))
        return new_lines.split("\n")