send2Line.py 文件源码

def sendData(form_field):
    url = "https://api.line.me/v2/bot/message/push"
    result = urlfetch.fetch(
        url=url,
        payload=json.dumps(form_field, ensure_ascii=False),
        method=urlfetch.POST,
        headers={
            'Content-type': 'application/json',
            'Authorization': 'Bearer ' + const.ChannelAccessToken
        }
    )
    if result.status_code == 200:
        logging.debug(result.content)
    else:
        logging.debug(result.content)