src.py 文件源码

python
阅读 25 收藏 0 点赞 0 评论 0

项目:PyCS 作者: COSMOGRAIL 项目源码 文件源码
def spline(self):
        """
        I return a new pycs.gen.spl.Spline object corresponding to the source.
        So this is a bit the inverse of the constructor.
        You can then put this spline object as ML of a lightcurve, as source spline, or whatever.

        Note that my output spline has LOTs of knots... it is an interpolating spline, not a regression spline !


        ..note:: This spline is a priori for display purposes only. To do an interpolation, it might be safer (and faster) to use
            the above linear interpolation eval() function.
            But making a plot, you'll see that this spline seems well accurate.
        """

        x = self.ijds.copy()
        y = self.imags.copy()
        magerrs = np.zeros(len(x))

        out = si.splrep(x, y, w=None, xb=None, xe=None, k=3, task=0, s=0.0, t=None, full_output=1, per=0, quiet=1)
        # s = 0.0 means interpolating spline !

        tck = out[0]

        # From this we want to build a real Spline object.
        datapoints = pycs.gen.spl.DataPoints(x, y, magerrs, splitup=False, sort=False, stab=False)
        outspline = pycs.gen.spl.Spline(datapoints, t = tck[0], c = tck[1], k = tck[2], plotcolour=self.plotcolour)

        # Conditions for the knots (no, everything is ok with them, no need to tweak anything).
        #intt = outspline.getintt()
        #outspline.setintt(intt)
        #print tck[2]
        #sys.exit()

        outspline.knottype = "MadeBySource"
        outspline.showknots = False # Usually we have a lot of them, slows down.
        return outspline
评论列表
文章目录


问题


面经


文章

微信
公众号

扫码关注公众号