database.py 文件源码

def nextref(cls, ea, count):
        '''Returns the next address from ``ea`` that has anything referencing it. Skip ``count`` references before returning.'''
        res = cls.walk(ea, cls.next, lambda n: len(xref.up(n)) == 0)
        return cls.nextref(cls.next(res), count-1) if count > 1 else res