fypp.py 文件源码

def _find_next_eol(output, ind):
        'Find last newline before current position.'
        # find first eol after expr. evaluation
        inext = ind + 1
        while inext < len(output):
            eolnext = output[inext].find('\n')
            if eolnext != -1:
                break
            inext += 1
        else:
            inext = len(output) - 1
            eolnext = len(output[-1]) - 1
        return inext, eolnext