explicit.py 文件源码

def closest(self, w, n=10):
        """
        Assumes the vectors have been normalized.
        """
        if self.oov(w):
            return []
        scores = self.m.dot(self.represent(w).T).T.tocsr()
        return heapq.nlargest(n, zip(scores.data, [self.iw[i] for i in scores.indices]))