transform.py 文件源码

def _estimate_lambda_single_y(y):
    """Estimate lambda for a single y, given a range of lambdas
    through which to search. No validation performed.

    Parameters
    ----------

    y : ndarray, shape (n_samples,)
       The vector being estimated against
    """

    # ensure is array
    y = np.array(y)

    # Use scipy's log-likelihood estimator
    b = boxcox(y, lmbda=None)

    # Return lambda corresponding to maximum P
    return b[1]