def nsmallest(n, iterable):
"""Find the n smallest elements in a dataset.
Equivalent to: sorted(iterable)[:n]
"""
if hasattr(iterable, '__len__') and n * 10 <= len(iterable):
# For smaller values of n, the bisect method is faster than a minheap.
# It is also memory efficient, consuming only n elements of space.
it = iter(iterable)
result = sorted(islice(it, 0, n))
if not result:
return result
insort = bisect.insort
pop = result.pop
los = result[-1] # los --> Largest of the nsmallest
for elem in it:
if cmp_lt(elem, los):
insort(result, elem)
pop()
los = result[-1]
return result
# An alternative approach manifests the whole iterable in memory but
# saves comparisons by heapifying all at once. Also, saves time
# over bisect.insort() which has O(n) data movement time for every
# insertion. Finding the n smallest of an m length iterable requires
# O(m) + O(n log m) comparisons.
h = list(iterable)
heapify(h)
return map(heappop, repeat(h, min(n, len(h))))
# 'heap' is a heap at all indices >= startpos, except possibly for pos. pos
# is the index of a leaf with a possibly out-of-order value. Restore the
# heap invariant.
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