unicode.py 文件源码

def blocknum(ch):
    """Returns the unicode block number for ch, or None if ch has no block.

    >>> blocknum(u'a')
    0
    >>> blocknum(unichr(0x0b80))
    22
    >>> blocknum(unichr(2048))
    None
    """

    cp = ord(ch)
    i = bisect_right(_starts, cp) - 1
    end = _ends[i]
    if cp > end:
        return None
    return i