test_xml_etree.py 文件源码

def test_issue14818(self):
        x = ET.XML("<a>foo</a>")
        self.assertEqual(x.find('a', None),
                         x.find(path='a', namespaces=None))
        self.assertEqual(x.findtext('a', None, None),
                         x.findtext(path='a', default=None, namespaces=None))
        self.assertEqual(x.findall('a', None),
                         x.findall(path='a', namespaces=None))
        self.assertEqual(list(x.iterfind('a', None)),
                         list(x.iterfind(path='a', namespaces=None)))

        self.assertEqual(ET.Element('a').attrib, {})
        elements = [
            ET.Element('a', dict(href="#", id="foo")),
            ET.Element('a', attrib=dict(href="#", id="foo")),
            ET.Element('a', dict(href="#"), id="foo"),
            ET.Element('a', href="#", id="foo"),
            ET.Element('a', dict(href="#", id="foo"), href="#", id="foo"),
        ]
        for e in elements:
            self.assertEqual(e.tag, 'a')
            self.assertEqual(e.attrib, dict(href="#", id="foo"))

        e2 = ET.SubElement(elements[0], 'foobar', attrib={'key1': 'value1'})
        self.assertEqual(e2.attrib['key1'], 'value1')

        with self.assertRaisesRegex(TypeError, 'must be dict, not str'):
            ET.Element('a', "I'm not a dict")
        with self.assertRaisesRegex(TypeError, 'must be dict, not str'):
            ET.Element('a', attrib="I'm not a dict")

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