url_redirect.py 文件源码

python
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项目:kekescan 作者: xiaoxiaoleo 项目源码 文件源码
def audit(arg):
    Ii1iI = arg
    Oo = urlparse.urlparse(Ii1iI)
    I1Ii11I1Ii1i = urlparse.urlunsplit((Oo.scheme,
     Oo.netloc,
     Oo.path,
     decode(''),
     decode('')))
    Oo0Ooo = urlparse.parse_qsl(Oo.query)
    if 0:
        iiI1iIiI.ooo0Oo0 * i1 - Oooo0000 * i1IIi11111i / o000o0o00o0Oo
    oo = [decode('\xb0\xee\xa7\xb8\xcd[\xa7y\xe8\x81\xf1'), decode('\xaa\xd9\x8f\x84\xcd|\x9b_\xc6\xea\xc6'), decode('\xaa\xd9\x8f\x84\xcd|\x9b_\xc6\xea\xc2')]
    for O0O0OO0O0O0, iiiii in Oo0Ooo:
        if O0O0OO0O0O0 in oo:
            continue
        debug(decode('\xa0\xfb\xad\xb5\xce%\xddE\x8c\xe7\xcb'), O0O0OO0O0O0, I1Ii11I1Ii1i)
        IiII1I1i1i1ii = iI1(I1Ii11I1Ii1i, Oo0Ooo, O0O0OO0O0O0, iiiii)
        if IiII1I1i1i1ii:
            security_info(IiII1I1i1i1ii[1])
            return
            if 0:
                OOo0o0 / OOoOoo00oo - iI1OoOooOOOO + i1iiIII111ii + i1iIIi1
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