CREATE DATABASE test;
use test;
create table tb_grade(id int(3),name varchar(10),grade int(3));
insert into tb_grade(id,name,grade) values(1,'guanyu',85),(2,'liubei',80),(3,'zhangfei',90),(4,'caocao',100);
SELECT * FROM tb_grade;
创建表tb_grade,表中添加数据
mysql
阅读 46
收藏 0
点赞 0
评论 0
评论列表
文章目录