def lrelu(x,leak=0.2,name='lrelu'):
with tf.variable_scope(name):
f1=0.5 * (1+leak)
f2=0.5 * (1-leak)
return f1*x + f2*tf.abs(x)
#This takes more memory than above
#def lrelu(x, leak=0.2, name="lrelu"):
# return tf.maximum(x, leak*x)
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