meta.py 文件源码

def source(self, command : str = None):
        '''
        Displays my full source code or for a specific command
        To display the source code of a subcommand you have to separate it by
        periods, e.g. tag.create for the create subcommand of the tag command
        Based on [R. Danny](https://github.com/Rapptz/RoboDanny)'s source command
        '''
        source_url = "https://github.com/Harmon758/Harmonbot"
        if command is None:
            await self.bot.embed_reply(source_url)
            return
        code_path = command.split('.')
        obj = self.bot
        for cmd in code_path:
            try:
                obj = obj.get_command(cmd)
                if obj is None:
                    await self.bot.embed_reply("Could not find the command " + cmd)
                    return
            except AttributeError:
                await self.bot.embed_reply("{0.name} command has no subcommands".format(obj))
                return
        # since we found the command we're looking for, presumably anyway, let's
        # try to access the code itself
        src = obj.callback.__code__
        lines, firstlineno = inspect.getsourcelines(src)
        ## if not obj.callback.__module__.startswith("discord"):
        # not a built-in command
        location = os.path.relpath(src.co_filename).replace('\\', '/')
        ## else:
        ##  location = obj.callback.__module__.replace('.', '/') + ".py"
        ##  source_url = "https://github.com/Rapptz/discord.py"
        final_url = '<{}/blob/master/Discord/{}#L{}-L{}>'.format(source_url, location, firstlineno, firstlineno + len(lines) - 1)
        await self.bot.embed_reply(final_url)