zipfile.py 文件源码

def _get_codename(self, pathname, basename):
        """Return (filename, archivename) for the path.

        Given a module name path, return the correct file path and
        archive name, compiling if necessary.  For example, given
        /python/lib/string, return (/python/lib/string.pyc, string).
        """
        file_py  = pathname + ".py"
        file_pyc = pathname + ".pyc"
        file_pyo = pathname + ".pyo"
        if os.path.isfile(file_pyo) and \
                            os.stat(file_pyo).st_mtime >= os.stat(file_py).st_mtime:
            fname = file_pyo    # Use .pyo file
        elif not os.path.isfile(file_pyc) or \
             os.stat(file_pyc).st_mtime < os.stat(file_py).st_mtime:
            import py_compile
            if self.debug:
                print "Compiling", file_py
            try:
                py_compile.compile(file_py, file_pyc, None, True)
            except py_compile.PyCompileError,err:
                print err.msg
            fname = file_pyc
        else:
            fname = file_pyc
        archivename = os.path.split(fname)[1]
        if basename:
            archivename = "%s/%s" % (basename, archivename)
        return (fname, archivename)